compilation error message on tomcat 5.5.27

[phil89]

Hi

I have change tomcat 5.5.26 to 5.5.27 and i have following compilation
error message

Code :

org.apache.jasper.JasperException: /jsp/servlet24/supervisionv2.jsp
(180,35) Attribute value ((servlet24.PosteBean)context.getPoste
("******")).getCodePoste()+"_appletc" is quoted with " which must be
escaped when used within the value
org.apache.jasper.compiler.DefaultErrorHandler.jspError
(DefaultErrorHandler.java:40)
org.apache.jasper.compiler.ErrorDispatcher.dispatch
(ErrorDispatcher.java:407)

Line is
<jsplugin type="applet" jreversion="1.4"
code="dclock.LedClock.class" archive="dclock.jar" height="36"
width="166">
<jsparams>

<jsparam name="name" value="<%= ((servlet24.PosteBean)
context.getPoste("******")).getCodePoste()+"_appletc"%>" />
</jsparams>



<jsp:fallback>
<p>Unable to load applet</p>
</jsp:fallback>
</jsplugin>

Could you help me ?

Regards
Philippe

 

[GArlington]

Hi

I have change tomcat 5.5.26 to 5.5.27 and i have following compilation
error message

Code :

org.apache.jasper.JasperException: /jsp/servlet24/supervisionv2.jsp
(180,35) Attribute value  ((servlet24.PosteBean)context.getPoste
("******")).getCodePoste()+"_appletc" is quoted with " which must be
escaped when used within the value
 org.apache.jasper.compiler.DefaultErrorHandler.jspError
(DefaultErrorHandler.java:40)
 org.apache.jasper.compiler.ErrorDispatcher.dispatch
(ErrorDispatcher.java:407)

Line is
<jsplugin type="applet" jreversion="1.4"
code="dclock.LedClock.class" archive="dclock.jar" height="36"
width="166">
 <jsparams>

  <jsparam name="name" value="<%= ((servlet24.PosteBean)
context.getPoste("******")).getCodePoste()+"_appletc"%>" />
     </jsparams>

What is NOT clear? What does your error message say? What does it
suggest?
(You have double quotes ["] within double quoted string), you can
either escape any double quotes used within the string, or change the
quotes to single quotes ['] around main string as bellow, AFAIR it
will work too...
<jsparam name="name" value='<%= ((servlet24.PosteBean)
context.getPoste("******")).getCodePoste()+"_appletc"%>' />

 

[TSG Todd]

Hi

I have change tomcat 5.5.26 to 5.5.27 and i have following compilation
error message

Code :

org.apache.jasper.JasperException: /jsp/servlet24/supervisionv2.jsp
(180,35) Attribute value  ((servlet24.PosteBean)context.getPoste
("******")).getCodePoste()+"_appletc" is quoted with " which must be
escaped when used within the value
 org.apache.jasper.compiler.DefaultErrorHandler.jspError
(DefaultErrorHandler.java:40)
 org.apache.jasper.compiler.ErrorDispatcher.dispatch
(ErrorDispatcher.java:407)

Line is
<jsplugin type="applet" jreversion="1.4"
code="dclock.LedClock.class" archive="dclock.jar" height="36"
width="166">
 <jsparams>

  <jsparam name="name" value="<%= ((servlet24.PosteBean)
context.getPoste("******")).getCodePoste()+"_appletc"%>" />
     </jsparams>

What is NOT clear? What does your error message say? What does it
suggest?
(You have double quotes ["] within double quoted string), you can
either escape any double quotes used within the string, or change the
quotes to single quotes ['] around main string as bellow, AFAIR it
will work too...
<jsparam name="name" value='<%= ((servlet24.PosteBean)
context.getPoste("******")).getCodePoste()+"_appletc"%>' />
</jsparams>

 <jsp:fallback>
  <p>Unable to load applet</p>
 </jsp:fallback>
</jsplugin>

Could you help me ?

Regards
Philippe

Well, my question would be, WHY did this work in Tomcat 5.5.26? Also,
Tomcat 5.0.28 and something in the WLS 9 family?