Determining version of OpenSSL linked against python?

[Adam Mercer]

Hi

I'm trying to write a script that determines the version of OpenSSL
that python is linked against, using python-2.7 this is easy as I can
use:

import ssl
ssl.OPENSSL_VERSION

but unfortunately I need to support python-2.6, from an older script I
used the following:

import _ssl
ssl_lib = _ssl.__file__

to get the path to the _ssl.so module and then I parsed the output of
ldd (on linux) to get the path to the OpenSSL library and then parsed
the version from the filename. In other words it's very messy.

I had a little success using this approach but I have recently
received a bug report that this doesn't seem to work on Debian
Squeeze. When I try to query the __file__ attribute of the _ssl module
I get the following error:
Traceback (most recent call last):

Can anyone offer any suggestions as to what is going wrong with the
above code or offer an alternative way of determining the OpenSSl
version using python-2.6?

Cheers

Adam

 

[Anssi Saari]

Can anyone offer any suggestions as to what is going wrong with the
above code or offer an alternative way of determining the OpenSSl
version using python-2.6?

I suppose you could use ctypes to load the library and call SSLeay()
which returns the OpenSSL version number as a C long.

Like this:

from ctypes import *
libssl = cdll.LoadLibrary("libssl.so")
openssl_version = libssl.SSLeay()
print "%.9X" % openssl_version

This gives me 0009080FF which corresponds to 0.9.8o release which is
what I have installed in Debian Squeeze.

 

[Adam Mercer]

I suppose you could use ctypes to load the library and call SSLeay()
which returns the OpenSSL version number as a C long.

Like this:

from ctypes import *
libssl = cdll.LoadLibrary("libssl.so")
openssl_version = libssl.SSLeay()
print "%.9X" % openssl_version

This gives me 0009080FF which corresponds to 0.9.8o release which is
what I have installed in Debian Squeeze.

Thanks, that looks useful.

Cheers

Adam