eval ? ['LBBW': checked]

H

Holger Joukl

You can use the exec statement (note that I set the if-condition to
1=true for the example, and I used different names for outer and inner
loop indexes):
.... list = []
.... for inner in range(1,7):
.... if 1:
.... list.append(inner)
.... foo = "list_" + str(index) + "= list"
.... exec foo
....
list_1 [1, 2, 3, 4, 5, 6]
list_2 [1, 2, 3, 4, 5, 6]
dir()
['__builtins__', '__doc__', '__name__', 'foo', 'index', 'inner', 'list',
'list_1', 'list_2', 'list_3']{'list_3': [1, 2, 3, 4, 5, 6], 'index': 3, 'list_1': [1, 2, 3, 4, 5, 6],
'list_2': [1, 2, 3, 4, 5, 6], '__builtins__': <module '__builtin__'
(built-in)>, 'list': [1, 2, 3, 4, 5, 6], 'inner': 6, '__name__':
'__main__', 'foo': 'list_3= list', '__doc__': None}

__________________



I'm trying to use eval (is the right function? ) to generate empty lists
with different names(es. list_1, list_2, list_3, ...) in a loop similar
to:

for index in range(1,4):
list=[]
for index in range(1,7):
if <condition>:
list.append(1)
foo='list_'+str(index)+'=list'
eval(foo)

I am not a programmer as you probably see from the code and I do not
even know if this is the right approach to do that in Python (I used
this structure with Matlab that I want now to dismiss ...)

Any help?
Thanks
angelo

--
http://mail.python.org/mailman/listinfo/python-list



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