How do I catch ExpatError exception?

[Shuaib]

Hey!

I am getting this exception.

xml.parsers.expat.ExpatError

But I am not able to catch it with "except
xml.parsers.expat.ExpatError:" It says "NameError: global name 'xml' is
not defined".

I am also not able to catch it with "except ExpatError:" Gives
"NameError: global name 'xml' is not defined"

How do I catch it? (I am parsing an xml file)

Also, how do I get the line number where an exception was thrown?

Thanks.

 

[Mark Winrock]

Hey!

I am getting this exception.

xml.parsers.expat.ExpatError

But I am not able to catch it with "except
xml.parsers.expat.ExpatError:" It says "NameError: global name 'xml' is
not defined".

I am also not able to catch it with "except ExpatError:" Gives
"NameError: global name 'xml' is not defined"

How do I catch it? (I am parsing an xml file)

Have you imported xml.parsers.expat to get it properly scoped?

Also, how do I get the line number where an exception was thrown?

Try looking at the 'sys.exc_info' and the 'traceback' module
documentation. Also see Python Cookbook recipe Recipe 8.6. Getting More
Information from Tracebacks (Bryn Keller)

 

[Steve Holden]

Hey!

I am getting this exception.

xml.parsers.expat.ExpatError

But I am not able to catch it with "except
xml.parsers.expat.ExpatError:" It says "NameError: global name 'xml' is
not defined".

I am also not able to catch it with "except ExpatError:" Gives
"NameError: global name 'xml' is not defined"

How do I catch it? (I am parsing an xml file)

import xml.parsers.expat

That way the interpreter will be able to resolve the reference to the
exception.

Also, how do I get the line number where an exception was thrown?

#
# Exception traceback test
#
def r():
return 1/0

try:
print r()
except:
import sys
t, v, tb = sys.exc_info()

print "exception on line", tb.tb_lineno

regards
Steve

 

[Shuaib]

import xml.parsers.expat

Thanks, that worked.

def r():
return 1/0

try:
print r()
except:
import sys
t, v, tb = sys.exc_info()

print "exception on line", tb.tb_lineno

How do I get the helpful text that is thrown with the exception? Like
if the exception is " IOError: [Errno 2] No such file or directory:
'out.xml' "

How do I get the the text after IOError: ?

Thanks again.