How to launch a windows file from my javaApp?

[Tomas]

Hi,

How do you i.e launch a .txt file in windows from a java application? I've
tried with Runtime.getRuntime().exec("e:\\file\\bla.txt") without sucess.
With that line i only manage to launch .exe files. So how to do to launch
other types of files?

Regards
/Tomas

 

[Ike]

In Windows, if it is a registered file type, simply pass the full path to
the file to:

public static final void openFileAndExecuteAssociatedApplication(String
fullPathAndFileName){
try {
Process p = Runtime.getRuntime().exec("cmd /c start
"+fullPathAndFileName);
p.waitFor();
} catch (Throwable ex) {
ex.printStackTrace();
}
} // Ike

 

[Tomas]

Thanks now it works. But it can not find the file when there are blank spaces
in the directory names in the path like this:

e:\my files\bla.tx

Any idea how to solve that?

Regards Tomas

 

[Roedy Green]

But it can not find the file when there are blank spaces
in the directory names in the path like this:

if you are passing a command line to cmd or 4NT you need to use the
same quoting conventions you would it you were writing bat file.