How to make two-dimensional array put 'new' to use in C++?

[chajs226]

Hi everyone.. I'm doing programing a maze problem.
I want to make a maze(array[5][7]) that use two-dimensional array...

but I don't know this...

{
int *a[7];
a[7] = new int [5];
}

this is result in segmentation error


help me... Thanks.

 

[Victor Bazarov]

Hi everyone.. I'm doing programing a maze problem.
I want to make a maze(array[5][7]) that use two-dimensional array...

but I don't know this...

{
int *a[7];
a[7] = new int [5];
}

this is result in segmentation error

See FAQ.

V

 

[fungus]

{
int *a[7];
a[7] = new int [5];
}

this is result in segmentation error

When you create a[7] then elements are
in the range 0 to 6. "7" is past the end
of the array.

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It¡¯s a completely nonsensical process.

 

[Sean Fritz]

{
int *a[7];
a[7] = new int [5];
}

this is result in segmentation error

When you create a[7] then elements are
in the range 0 to 6. "7" is past the end
of the array.

Definitely have to be careful with array ranges in C++, most compilers won't
give you an error if you try to go outside the index.

 

[Salt_Peter]

Hi everyone.. I'm doing programing a maze problem.
I want to make a maze(array[5][7]) that use two-dimensional array...

but I don't know this...

{
int *a[7];
a[7] = new int [5];
}

this is result in segmentation error


help me... Thanks.

there are 7 numbers from 0 to 6 and 7 isn't one of them.

 

[David Harmon]

On 5 Jan 2007 21:06:10 -0800 in comp.lang.c++, "(e-mail address removed)"

Hi everyone.. I'm doing programing a maze problem.
I want to make a maze(array[5][7]) that use two-dimensional array...

Avoid 'new' and bare naked arrays in application-level code.

std::vector< std::vector<int> > array(5, std::vector<int>(7));