Put a url in a browsers address bar

[Colin Gillespie]

Dear All,

I would like to place a url in my browsers address bar, then execute.
How can do this?

e.g.

def goToGoogle():
url = "www.google.com"
b = openBrowser()
b.goToUrl(url)
return True

Thanks for any help

Colin

 

[Alan Kemp]

I would like to place a url in my browsers address bar, then execute.
How can do this?

e.g.

def goToGoogle():
url = "www.google.com"
b = openBrowser()
b.goToUrl(url)
return True

def goToGoogle():
import webbrowser
webbrowser.open("www.google.com");

Alan

 

[Colin Gillespie]

def goToGoogle():
import webbrowser
webbrowser.open("www.google.com");

Thanks for the quick reply. Do you know what module I would use to fill
out a form on an open web page?

Thanks

Colin

 

[Peter Hansen]

Thanks for the quick reply. Do you know what module I would use to fill
out a form on an open web page?

The answer involves Google again, but this time it is "Use Google Groups
to search the archives for previous answers to questions like yours",
which is good advice to follow most of the time when you have a question
that seems likely to have been asked before.

Try this search pattern for a start "python fill out form on web page".

(Note, Google Groups, not just Google.)

-Peter

 

[Steve Holden]

Thanks for the quick reply. Do you know what module I would use to fill
out a form on an open web page?

Thanks

Colin

You could take a look at John Lee's ClientForm module. Start at

http://wwwsearch.sourceforge.net/ClientForm/

regards
Steve

 

[Steve Holden]

Thanks for the quick reply. Do you know what module I would use to fill
out a form on an open web page?

Thanks

Colin

Oops. ClientForm expects you to be interacting directly with the server,
not driving an open browser window. To do the same thing through the
browser would involve using COM, I suspect. If so be careful, as what
you implement may end up being browser-specific.

regards
Steve

 

[ina]

Here is a start.

http://www.ishpeck.net/?P=pytesting
This is all stuff based on windos.