Question about using "with"

[Steven W. Orr]

From the tutorial, they said that the following construct will
automatically close a previously open file descriptor:

-------------------
#! /usr/bin/python
import sys

for nn in range ( 1, len(sys.argv ) ):
print "arg ", nn, "value = ", sys.argv[nn]
with open(sys.argv[nn]) as f:
for line in f:
print line,
------------------

but when I run it (with args) I get:

591 > ./cat.py cat.py
File "./cat.py", line 6
with open(sys.argv[nn]) as f:
^
SyntaxError: invalid syntax
592 >

This example came from http://docs.python.org/tut/node10.html down in
section 8.7

Am I missing something?

TIA

--
Time flies like the wind. Fruit flies like a banana. Stranger things have .0.
happened but none stranger than this. Does your driver's license say Organ ..0
Donor?Black holes are where God divided by zero. Listen to me! We are all- 000
individuals! What if this weren't a hypothetical question?
steveo at syslang.net

 

[Steven Bethard]

From the tutorial, they said that the following construct will

automatically close a previously open file descriptor:

-------------------
#! /usr/bin/python
import sys

for nn in range ( 1, len(sys.argv ) ):
print "arg ", nn, "value = ", sys.argv[nn]
with open(sys.argv[nn]) as f:
for line in f:
print line,
------------------

but when I run it (with args) I get:

591 > ./cat.py cat.py
File "./cat.py", line 6
with open(sys.argv[nn]) as f:
^
SyntaxError: invalid syntax
592 >

This example came from http://docs.python.org/tut/node10.html down in
section 8.7

Am I missing something?

You need to enable the with statement using a __future__ import::
<stdin>:1: Warning: 'with' will become a reserved keyword in Python 2.6
File "<stdin>", line 1
with open('temp.txt', 'w') as f:
^
SyntaxError: invalid syntax.... f.write('hello')
....

STeVe

 

[Peter Otten]

From the tutorial, they said that the following construct will

automatically close a previously open file descriptor:

-------------------
#! /usr/bin/python
import sys

for nn in range ( 1, len(sys.argv ) ):
print "arg ", nn, "value = ", sys.argv[nn]
with open(sys.argv[nn]) as f:
for line in f:
print line,
------------------

but when I run it (with args) I get:

591 > ./cat.py cat.py
File "./cat.py", line 6
with open(sys.argv[nn]) as f:
^
SyntaxError: invalid syntax
592 >

This example came from http://docs.python.org/tut/node10.html down in
section 8.7

Am I missing something?

The with-statement only works in Python 2.5, and you have to enable it
explicitly:
.... print len(f.read())
....
15Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: I/O operation on closed file

Peter