regex replace hex with &#ddd;

[John]

Hi

$x =~s |([xc0-xff])|\&\#ord($1)\;|eg;

I'm trying to replace any character C0 to FF with

I cannot get the ord to evaluate. I have appended the 'e'

Any idea what I'm doing wrong?

Regards
John

 

[sln]

Hi

$x =~s |([xc0-xff])|\&\#ord($1)\;|eg;

I'm trying to replace any character C0 to FF with

I cannot get the ord to evaluate. I have appended the 'e'

Any idea what I'm doing wrong?

Regards
John

When its evaled it needs to be quoted.
Don't forget to escape the hex notation.

$x = "\xc0 \xff";
$x =~s |([\xc0-\xff])|'&#'.ord($1).';'|eg;
print $x;

-sln

 

[John]

Hi

$x =~s |([xc0-xff])|\&\#ord($1)\;|eg;

I'm trying to replace any character C0 to FF with

I cannot get the ord to evaluate. I have appended the 'e'

Any idea what I'm doing wrong?

Regards
John

When its evaled it needs to be quoted.
Don't forget to escape the hex notation.

$x = "\xc0 \xff";
$x =~s |([\xc0-\xff])|'&#'.ord($1).';'|eg;
print $x;

-sln

Many thanks. I completely messed up the second half. But I see the
solution now.

Regards
John