template specialization - member function

[graham]

Hi ,

I have two questions.

Given a template class like this;

template <typename T1, typename T2>
class Example
{

public:

template<typename BAR>;
void foo(BAR& seq);
};


1) Is there anything wrong with this type of class declaration? I have
class instances parameterized by T1 and T2 and instances of these can
call foo with other types of parameters. My client code will be like
this (or at least I want it to be )

Example<int, long> egIntLong;

std::string str;
egIntLong.foo(str);


Ive greatly simplified obviously, but I hope this conveys what I want
to do. Don't ask me the why I want it that way, I just do

2) What should the signatture of foo bee when implemented in a .cpp
file? I can't get it right!!

thanks and have a nice day

Graham

 

[graham]

Hi ,

I have two questions.

Given a template class like this;

template <typename T1, typename T2>
class  Example
{

public:

  template<typename BAR>;
  void foo(BAR& seq);

};

1) Is there anything wrong with this type of class declaration? I have
class instances parameterized by T1 and T2 and instances of these can
call foo with other types of  parameters. My client code will be like
this (or at least I want it to be )

Example<int, long> egIntLong;

std::string str;
egIntLong.foo(str);

Ive greatly simplified obviously, but I hope this conveys what I want
to do. Don't ask me the why I want it that way, I just do

2)  What should the signatture of foo bee when implemented in a .cpp
file? I can't get it right!!

thanks and have a nice day

Graham

Sokay, I got it...