Boost::Thread: Joining without waiting

[Hans Mull]

Hi!
I'm experimenting with boost::thread. I have a GUI application with a
slot function:

void someFunction(){...}
void Frame::OnOkButtonClick(...)
{
switch(someInteger)
{
case 0: break
case 1:
{
boost::thread mthTread(&someFunction);
mthTread.join();
break;
}
default: break
}
}

The program compiles and runs properly, but the GUI doesn't react
(Well, this is what to expect with this code because it waits for the
Thread to finish).
How can I make the program not to wait until the thread is finished?
Thanks in advance!

Kind regards, Hans

 

[Michael DOUBEZ]

Hans Mull a écrit :

Hi!
I'm experimenting with boost::thread. I have a GUI application with a
slot function:

void someFunction(){...}
void Frame::OnOkButtonClick(...)
{
switch(someInteger)
{
case 0: break
case 1:
{
boost::thread mthTread(&someFunction);
mthTread.join();
break;
}
default: break
}
}

The program compiles and runs properly, but the GUI doesn't react
(Well, this is what to expect with this code because it waits for the
Thread to finish).
How can I make the program not to wait until the thread is finished?

Don't call join(). The thread will remain in detached state.

Michael

 

[Hans Mull]

Hans Mull a écrit :

Don't call join(). The thread will remain in detached state.

Michael

Thar worked well, thank you!