const char* = new char[6]

[Frederick Gotham]

S S posted:

A const* p = new A const[3](5);

What compiler are you using? G++ gives:

ISO C++ forbids initialization in array new

 

[Frederick Gotham]

S S posted:

Even if you do not put brackets () and write
int *p = new int[3];
then also it does the default initialisation for all 3 members of
array, any significance of brackets?

The Standard provides no such guarantee (well I'm 99% that it doesn't) --
if you want each element to be default-initialised, you'll have to use the
empty parentheses.

Testing it will do you no good, as I know of at least one implementation
that default-initialises new'ed memory regardless of whether you provide
the empty parentheses.

Anyhow, even if the empty parentheses were redundant, I would still put
them in, just as how I write:

int main()
{
static MyPOD arr[5] = {};
}

instead of:

int main()
{
static MyPOD arr[5];
}

Indeed, the chain brackets are redundant because static data always gets
default initialised... but nonetheless, they express clear intent.

 

[Noah Roberts]

Frederick Gotham wrote:

int *p = new int[3]();

Even if you do not put brackets () and write
int *p = new int[3];
then also it does the default initialisation for all 3 members of
array, any significance of brackets?

You are mistaken. No initialization occurs if the parens are not
there. Not even default initialization.