Datetime objects

[Lad]

How can I find days and minutes difference between two datetime
objects?
For example If I have
b=datetime.datetime(2006, 8, 2, 8, 57, 28, 687000)
a=datetime.datetime(2006, 8, 1, 18, 19, 45, 765000)

Thank you for help
L.

 

[Sybren Stuvel]

Lad enlightened us with:

How can I find days and minutes difference between two datetime
objects?
For example If I have
b=datetime.datetime(2006, 8, 2, 8, 57, 28, 687000)
a=datetime.datetime(2006, 8, 1, 18, 19, 45, 765000)

diff = b - a

Check out http://docs.python.org/lib/datetime-datetime.html especially
the part called "supported operations".

Sybren

 

[Diez B. Roggisch]

How can I find days and minutes difference between two datetime
objects?
For example If I have
b=datetime.datetime(2006, 8, 2, 8, 57, 28, 687000)
a=datetime.datetime(2006, 8, 1, 18, 19, 45, 765000)

a - b

Lookup datetime.timedelta - all of this is neatly documented.

Diez

 

[Lad]

Lad enlightened us with:

diff = b - a

Ok, I tried
datetime.timedelta(-999999999)


which is not good for me.

So I tried to use toordinal like this
diff=b.toordinal()-a.toordinal()

but I get
diff=1

Why?
where do I make a mistake?
Thank you for help

 

[John Machin]

Ok, I tried

datetime.timedelta(-999999999)

Reread the manual:

1. "min" is minIMUM, not minUTES

2. You need:

which is not good for me.

So I tried to use toordinal like this
diff=b.toordinal()-a.toordinal()

but I get
diff=1

Why?

because toordinal() works only on the date part, ignoring the time
part.

HTH,
John

 

[Lad]

Reread the manual:

1. "min" is minIMUM, not minUTES

2. You need:

because toordinal() works only on the date part, ignoring the time
part.

HTH,
John

Thank you for the explanation