E
Edward Diener
In Windows Vista x64 I have installed python 2.6 64-bit version and
python 3.1 64-bit version to separate folders. Within the command
interpreter I add python 2.6 to the PATH.
In the command interpreter, When I type python somescript.py with an
import sys
print (sys.version)
in the script, it shows:
3.1.2 (r312:79149, Mar 20 2010, 22:55:39) [MSC v.1500 64 bit (AMD64)]
In the command interpreter if I type 'python' I see:
Python 2.6.5 (r265:79096, Mar 19 2010, 18:02:59) [MSC v.1500 64 bit
(AMD64)] on win32
Does anybody have any ideas why this is happening ?
python 3.1 64-bit version to separate folders. Within the command
interpreter I add python 2.6 to the PATH.
In the command interpreter, When I type python somescript.py with an
import sys
print (sys.version)
in the script, it shows:
3.1.2 (r312:79149, Mar 20 2010, 22:55:39) [MSC v.1500 64 bit (AMD64)]
In the command interpreter if I type 'python' I see:
Python 2.6.5 (r265:79096, Mar 19 2010, 18:02:59) [MSC v.1500 64 bit
(AMD64)] on win32
Does anybody have any ideas why this is happening ?