Does python support the expression "a = b | 1"???

[Wenhua Zhao]

a = b | 1

a = b if b != nil
else a =1

Is there such expression in python?

Thanks a lot!

 

[Diez B. Roggisch]

a = b | 1

a = b if b != nil
else a =1

Is there such expression in python?

Soon there will be, but currently: no. What you are after is a ternary
operator like _?_:_ in C. There have been plenty of discussions about
these - search this NG. Depending on your usecase, either

if b is not None:
a = b
else:
a = 1

or

a = [1,b][b is not None]

or even

a = b or 1

will do the trick.

But PLEASE read the discussions first, to understand the reasons and
implications.

Diez

 

[=?iso-8859-1?Q?Fran=E7ois?= Pinard]

[Wenhua Zhao]

a = b | 1

a = b if b != nil
else a =1

Is there such expression in python?

Hi. Merely write:

a = b or 1

In Python, there is no `nil'. `a' will receive 1 instead of the value of
`b' only if `b' is either zero, None, False, or empty in some way.

 

[Paul Rubin]

Is there such expression in python?

Not in the current version but one is being added.

 

[Grant Edwards]

a = b | 1

Yes, Python supports that expression.

a = b if b != nil
else a =1

But that's not what it means.

Is there such expression in python?

I'm not sure what What you mean by "nil", but I would geuess
this is the equivalent Python:

if b is not None:
a = b
else:
a = 1