Finding the Precision of Doubles

[mvelez999]

Hello,

I am trying to find the smallest 'delta' value that makes the following equation evaluate to TRUE.
***Let x be a double***
x + 'delta' != x

This is the code I wrote. Can somebody help me figure out why it stops after 1 execution of the WHILE loop?

#include <iostream>

using namespace std;

void main()
{
int i=1;
double x=1;
while (x != (x + (1/i)))
{
i++;
}
cout << "I equals " << i << endl;
//cout << "Delta equals " << 1/(i-1) << endl;
}

Result: I equals 2

****This next snippet stops after 1 execution as well (different code, same math). LOL.****

void main()
{
int i=1;
double x=1;
double y = x + (1/i);
while (x != y)
{
i++;
y = x + (1/i);
}
cout << "I equals " << i << endl;
//cout << "Delta equals " << 1/i << endl;
}

RESULT: I equals 2
Thanks in advance.

 

[mvelez999]

New Attempt

This is the newest code that I have tried. It still does not work. LOL.
void main()
{
double i=2000000000;
double delta = 1/i;
int x=1;
cout << "Original Delta " << delta << endl;
while (x != (x + delta))
{
if (((int) i % 100000) == 0)
{
cout << "I equals " << i << endl;
cout << "Delta equals " << delta << endl;
}
i++;
delta = 1/i;
}
cout << "Final I equals " << i << endl;
cout << "Final Delta equals " << delta << endl;
}

Final RESULTS:
I equals 2.1472e+009
Delta equals 4.65679e-010

The results that I am expecting are:
Final I equals . . .
Final Delta equals . . .

Why isn't this printing after the while loops ends? Or does the while never end?