HTTP post with urllib2

[cerr]

Hi,

Why does this code:

#!/usr/bin/python


import urllib2
from binascii import hexlify, unhexlify

host = "localhost"
uri="/test.php"
data ="\x48\x65\x6C\x6C\x6F\x57\x6F\x72\x6C\x64" #Hello World
url="http://{0}{1}?f=test".format(host, uri)
req = urllib2.Request(url, data,{'Content-Type': 'application/octet-stream'})
req.get_method = lambda: 'PUT'
response = urllib2.urlopen(req, 120)
retval = response.read()
print "RETVAL "+retval



return me this:

../post.py
Traceback (most recent call last):
File "./post.py", line 13, in <module>
response = urllib2.urlopen(req, 120)
File "/usr/lib/python2.7/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "/usr/lib/python2.7/urllib2.py", line 398, in open
req = meth(req)
File "/usr/lib/python2.7/urllib2.py", line 1116, in do_request_
'Content-length', '%d' % len(data))


I don't get it, what's going on here?

Thank you!

 

[Joel Goldstick]

Hi,

Why does this code:

#!/usr/bin/python


import urllib2
from binascii import hexlify, unhexlify

host = "localhost"
uri="/test.php"
data ="\x48\x65\x6C\x6C\x6F\x57\x6F\x72\x6C\x64" #Hello World
url="http://{0}{1}?f=test".format(host, uri)
req = urllib2.Request(url, data,{'Content-Type': 'application/octet-stream'})
req.get_method = lambda: 'PUT'

What does the above line do? is it the same as req.get_method = 'PUT'

response = urllib2.urlopen(req, 120)

the docs say req should be a url. Is it?

retval = response.read()
print "RETVAL "+retval



return me this:

./post.py
Traceback (most recent call last):
File "./post.py", line 13, in <module>
response = urllib2.urlopen(req, 120)
File "/usr/lib/python2.7/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "/usr/lib/python2.7/urllib2.py", line 398, in open
req = meth(req)
File "/usr/lib/python2.7/urllib2.py", line 1116, in do_request_
'Content-length', '%d' % len(data))


I don't get it, what's going on here?

Thank you!

KInda of ducking your questions, but the requests module is a lot
easier to use and
understand:http://docs.python-requests.org/en/latest/

 

[cerr]

What does the above line do? is it the same as req.get_method = 'PUT'

I guess so, I got this from an example.... copy & paste :x

the docs say req should be a url. Is it?

no, it's an instance of req = urllib2.Request()

KInda of ducking your questions, but the requests module is a lot

easier to use and

understand:http://docs.python-requests.org/en/latest/

But there must be a way to get this working with urllib alone...

 

[MRAB]

Hi,

Why does this code:

#!/usr/bin/python


import urllib2
from binascii import hexlify, unhexlify

host = "localhost"
uri="/test.php"
data ="\x48\x65\x6C\x6C\x6F\x57\x6F\x72\x6C\x64" #Hello World
url="http://{0}{1}?f=test".format(host, uri)
req = urllib2.Request(url, data,{'Content-Type': 'application/octet-stream'})
req.get_method = lambda: 'PUT'
response = urllib2.urlopen(req, 120)
retval = response.read()
print "RETVAL "+retval



return me this:

./post.py
Traceback (most recent call last):
File "./post.py", line 13, in <module>
response = urllib2.urlopen(req, 120)
File "/usr/lib/python2.7/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "/usr/lib/python2.7/urllib2.py", line 398, in open
req = meth(req)
File "/usr/lib/python2.7/urllib2.py", line 1116, in do_request_
'Content-length', '%d' % len(data))


I don't get it, what's going on here?

The docs say """urllib2.urlopen(url[, data][, timeout])""".

You're calling it as """urllib2.urlopen(req, 120)""".

In other words, 'url' is req and 'data' is 120.

It should be """urllib2.urlopen(req, None, 120)""".

 

[Chris Angelico]

./post.py
Traceback (most recent call last):
File "./post.py", line 13, in <module>
response = urllib2.urlopen(req, 120)
File "/usr/lib/python2.7/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "/usr/lib/python2.7/urllib2.py", line 398, in open
req = meth(req)
File "/usr/lib/python2.7/urllib2.py", line 1116, in do_request_
'Content-length', '%d' % len(data))


I don't get it, what's going on here?

You've given a traceback without the actual error. MRAB happened to
figure out the mistake just from what you posted, but in future, do
try to copy a bit more down

ChrisA

 

[cerr]

Hi,

Why does this code:




import urllib2

from binascii import hexlify, unhexlify

host = "localhost"

data ="\x48\x65\x6C\x6C\x6F\x57\x6F\x72\x6C\x64" #Hello World

url="http://{0}{1}?f=test".format(host, uri)

req = urllib2.Request(url, data,{'Content-Type': 'application/octet-stream'})

req.get_method = lambda: 'PUT'

response = urllib2.urlopen(req, 120)

retval = response.read()

print "RETVAL "+retval



return me this:


Traceback (most recent call last):

File "./post.py", line 13, in <module>

response = urllib2.urlopen(req, 120)

File "/usr/lib/python2.7/urllib2.py", line 126, in urlopen

return _opener.open(url, data, timeout)

File "/usr/lib/python2.7/urllib2.py", line 398, in open

req = meth(req)

File "/usr/lib/python2.7/urllib2.py", line 1116, in do_request_

'Content-length', '%d' % len(data))


I don't get it, what's going on here?

The docs say """urllib2.urlopen(url[, data][, timeout])""".



You're calling it as """urllib2.urlopen(req, 120)""".



In other words, 'url' is req and 'data' is 120.



It should be """urllib2.urlopen(req, None, 120)""".

Yes, great! That did it!
Coming into the office in the morning, sitting down, changing this and get it working! Good way to start my day!

Thanks MRAB!