re.search over a list

[Bruno Desthuilliers]

Pat a écrit :

While I can use a for loop looking for a match on a list, I was
wondering if there was a one-liner way.

In particular, one of my RE's looks like this '^somestring$' so I can't
just do this: re.search( '^somestring$', str( mylist ) )

I'm not smart enough (total newbie) to code up a generator expression
and I was wondering if I'm missing something obvious.

words = ['foo', 'bar', 'somestring', 'baaz']
re.search(r"^somestring$", "\n".join(words), re.MULTILINE)

I love succinct but clearly understandable code.

separator.join(sequence_of_strings) is a very common python idiom, so
you can consider it as readable.

 

[Pat]

While I can use a for loop looking for a match on a list, I was
wondering if there was a one-liner way.

In particular, one of my RE's looks like this '^somestring$' so I can't
just do this: re.search( '^somestring$', str( mylist ) )

I'm not smart enough (total newbie) to code up a generator expression
and I was wondering if I'm missing something obvious.

I love succinct but clearly understandable code.

thx!

 

[Pat]

Pat a écrit :

While I can use a for loop looking for a match on a list, I was
wondering if there was a one-liner way.

In particular, one of my RE's looks like this '^somestring$' so I
can't just do this: re.search( '^somestring$', str( mylist ) )

I'm not smart enough (total newbie) to code up a generator expression
and I was wondering if I'm missing something obvious.

words = ['foo', 'bar', 'somestring', 'baaz']
re.search(r"^somestring$", "\n".join(words), re.MULTILINE)

I love succinct but clearly understandable code.

separator.join(sequence_of_strings) is a very common python idiom, so
you can consider it as readable.

That's excellent. Exactly what I was looking for.

Thank you VERY much!

 

[Bruno Desthuilliers]

Pat a écrit :

Pat a écrit :

While I can use a for loop looking for a match on a list, I was
wondering if there was a one-liner way.

In particular, one of my RE's looks like this '^somestring$' so I
can't just do this: re.search( '^somestring$', str( mylist ) )

I'm not smart enough (total newbie) to code up a generator expression
and I was wondering if I'm missing something obvious.

words = ['foo', 'bar', 'somestring', 'baaz']
re.search(r"^somestring$", "\n".join(words), re.MULTILINE)

I love succinct but clearly understandable code.

separator.join(sequence_of_strings) is a very common python idiom, so
you can consider it as readable.

That's excellent. Exactly what I was looking for.

Thank you VERY much!

Note that at least for this exact case, you don't need re at all:
True

But I guess you do have some less trivial use case !-)

 

[Steve Holden]

Pat a écrit :

While I can use a for loop looking for a match on a list, I was
wondering if there was a one-liner way.

In particular, one of my RE's looks like this '^somestring$' so I
can't just do this: re.search( '^somestring$', str( mylist ) )

I'm not smart enough (total newbie) to code up a generator expression
and I was wondering if I'm missing something obvious.

words = ['foo', 'bar', 'somestring', 'baaz']
re.search(r"^somestring$", "\n".join(words), re.MULTILINE)

I love succinct but clearly understandable code.

separator.join(sequence_of_strings) is a very common python idiom, so
you can consider it as readable.

That's excellent. Exactly what I was looking for.

I suspect that

any(re.match(pat, word) for word in words)

might be a more efficient way to do this.

regards
Steve

 

[Bruno Desthuilliers]

Steve Holden a écrit :

Bruno Desthuilliers wrote: (snip)

words = ['foo', 'bar', 'somestring', 'baaz']
re.search(r"^somestring$", "\n".join(words), re.MULTILINE)

(snip)

I suspect that

any(re.match(pat, word) for word in words)

might be a more efficient way to do this.

Indeed. I'm not yet used to have all and any builtins, thanks for the
reminder.

 

[Pat]

Pat a écrit :

Pat a écrit :
While I can use a for loop looking for a match on a list, I was
wondering if there was a one-liner way.

In particular, one of my RE's looks like this '^somestring$' so I
can't just do this: re.search( '^somestring$', str( mylist ) )

I'm not smart enough (total newbie) to code up a generator
expression and I was wondering if I'm missing something obvious.

words = ['foo', 'bar', 'somestring', 'baaz']
re.search(r"^somestring$", "\n".join(words), re.MULTILINE)


I love succinct but clearly understandable code.

separator.join(sequence_of_strings) is a very common python idiom, so
you can consider it as readable.

That's excellent. Exactly what I was looking for.

Thank you VERY much!

Note that at least for this exact case, you don't need re at all:
True

But I guess you do have some less trivial use case !-)

I used re because I wanted a string that was not a substring, hence the
^$. In my trivial example, I used words but my intent was to search for
words within a longer string.