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Hi,
This seems to be a basic question but i would like to know why.
String concatenation in rails can be done in the following three ways:
1. a+b+c
2. a<<b<<c
3. "#{a}#{b}#{c}"
where a b c are three variables
Which is the good way to go about concatenation and why?
a+b+c is not good because it creates temp string objects i guess
But i would really like to know of the three which is better and why. Is
there any performance difference in using them
Thanks in advance
You can experiment using benchmark (see below) or hitimes (which I haven't
tried yet), and there may well be others. I think the results should be
taken more as indications rather than definitive, but you can see from the
following that whether one way is faster than another can depend on the
data. (I hope that the formatting of the times is ok - it looks diabolical
in this draft.)
require "benchmark"
r1 = r2 = r3 = nil
a = nil
av = "Karel Capek".freeze
b = " wrote"
c = " War with the Newts"
kt = 100_000
Benchmark.bmbm do |r|
r.report("a+b+c" ) {kt.times { a = av.dup; r1 = a + b + c } }
r.report("a<<b<<c" ) {kt.times { a = av.dup; r2 = a << b << c } }
r.report('#{a}#{b}#{c}') {kt.times { a = av.dup; r3 = "#{a}#{b}#{c}" } }
end
p r1, r2, r3
av = ("kc " * 100).freeze
b = " wr" * 50
c = " WN" * 50
kt = 100_000
Benchmark.bmbm do |r|
r.report("a+b+c" ) {kt.times { a = av.dup; r1 = a + b + c } }
r.report("a<<b<<c" ) {kt.times { a = av.dup; r2 = a << b << c } }
r.report('#{a}#{b}#{c}') {kt.times { a = av.dup; r3 = "#{a}#{b}#{c}" } }
end
##########=>
run: "C:\ruby19\bin\ruby.exe" -v "aaa-bm-str.rb"
ruby 1.9.1p243 (2009-07-16 revision 24175) [i386-mingw32]
Rehearsal ------------------------------------------------
a+b+c 0.405000 0.000000 0.405000 ( 0.470000)
a<<b<<c 0.406000 0.000000 0.406000 ( 0.410000)
#{a}#{b}#{c} 0.468000 0.000000 0.468000 ( 0.515000)
--------------------------------------- total: 1.279000sec
user system total real
a+b+c 0.452000 0.000000 0.452000 ( 0.465000)
a<<b<<c 0.390000 0.000000 0.390000 ( 0.395000)
#{a}#{b}#{c} 0.499000 0.000000 0.499000 ( 0.520000)
"Karel Capek wrote War with the Newts"
"Karel Capek wrote War with the Newts"
"Karel Capek wrote War with the Newts"
Rehearsal ------------------------------------------------
a+b+c 0.624000 0.016000 0.640000 ( 0.690000)
a<<b<<c 0.499000 0.000000 0.499000 ( 0.515000)
#{a}#{b}#{c} 0.671000 0.000000 0.671000 ( 0.650000)
--------------------------------------- total: 1.810000sec
user system total real
a+b+c 0.639000 0.000000 0.639000 ( 0.645000)
a<<b<<c 0.515000 0.031000 0.546000 ( 0.540000)
#{a}#{b}#{c} 0.624000 0.000000 0.624000 ( 0.680000)
