Substring from regexp

[Eduardo Yáñez Parareda]

Hi all,

how could I get a substring which match a regular expression?

I mean:

"assddHellOasddaffer".something(/^H.*O$) => HellO

 

[Marcin Mielżyński]

Hi all,

how could I get a substring which match a regular expression?

I mean:

"assddHellOasddaffer".something(/^H.*O$) => HellO

"assddHellOasddaffer"[/H.*O/]

lopex

 

[Eduardo Yáñez Parareda]

"assddHellOasddaffer"[/H.*O/]

Thanks, I'm newbie with Ruby but with regexps too!

Well, another question. Having this string


"fsdfadfdsf{1dffsdfadsf-}fsdfdsfa{1fsdfsdfsdfsdfsdh-}f"

if I split it with /1\{.*-\}/ I get:

["fsdfadfdsf", "f"]

that's right, but I want to get ["{1dffsdfadsf-}", "{1fsdfsdfsdfsdfsdh-}"] that's said, the inverse of split.
Might I change the regexp or is there any method I could use?

 

[Eduardo Yáñez Parareda]

"assddHellOasddaffer".match(/(H.+O)/)

puts $1

The parenthesis form groups for back-referencing. You don't want the ^
or $ in your Regexp because the pattern you're looking for isn't at the
beginning or end of a string.

Yes, I realized that after reading Marcin's answer...

 

[Robert Klemme]

"assddHellOasddaffer"[/H.*O/]

Thanks, I'm newbie with Ruby but with regexps too!

Well, another question. Having this string


"fsdfadfdsf{1dffsdfadsf-}fsdfdsfa{1fsdfsdfsdfsdfsdh-}f"

if I split it with /1\{.*-\}/ I get:

["fsdfadfdsf", "f"]

that's right,

Sure? I'd rather guess that you want three strings.

but I want to get ["{1dffsdfadsf-}",
"{1fsdfsdfsdfsdfsdh-}"] that's said, the inverse of split.
Might I change the regexp or is there any method I could use?

You want #scan:

irb(main):003:0>
"fsdfadfdsf{1dffsdfadsf-}fsdfdsfa{1fsdfsdfsdfsdfsdh-}f".scan /\{[^}]*\}/
=> ["{1dffsdfadsf-}", "{1fsdfsdfsdfsdfsdh-}"]
irb(main):004:0>
"fsdfadfdsf{1dffsdfadsf-}fsdfdsfa{1fsdfsdfsdfsdfsdh-}f".scan /\{.*?\}/
=> ["{1dffsdfadsf-}", "{1fsdfsdfsdfsdfsdh-}"]
irb(main):005:0>
"fsdfadfdsf{1dffsdfadsf-}fsdfdsfa{1fsdfsdfsdfsdfsdh-}f".scan /\{[^}]*?\}/
=> ["{1dffsdfadsf-}", "{1fsdfsdfsdfsdfsdh-}"]

Kind regards

robert


PS: It's usually better to post new questions to new threads.

 

[Eduardo Yáñez Parareda]

You want #scan:

Yes!, I tried it before post this message but may be with wrong regexp

PS: It's usually better to post new questions to new threads.

I'm sorry , better next time. Thanks a lot.

 

[Eduardo Yáñez Parareda]

"fsdfadfdsf{1dffsdfadsf-}fsdfdsfa{1fsdfsdfsdfsdfsdh-}f".scan /\{.*?\}/

=> ["{1dffsdfadsf-}", "{1fsdfsdfsdfsdfsdh-}"]

I think I'm bit tedious but why it doesn't work if I put some \n inside source string?
Is '\n' character not considered when using '.*' expression?

 

[Marcin Mielżyński]

"fsdfadfdsf{1dffsdfadsf-}fsdfdsfa{1fsdfsdfsdfsdfsdh-}f".scan /\{.*?\}/
=> ["{1dffsdfadsf-}", "{1fsdfsdfsdfsdfsdh-}"]

I think I'm bit tedious but why it doesn't work if I put some \n inside
source string?
Is '\n' character not considered when using '.*' expression?

use multiline option:

/.../m

lopex