use -e to check if file exists on win32

[mynews]

The c:/dir is exist.

print -e 'C:/dir/"';
the result is 1 ,why?

print -e 'C:/"';
the result is null

This is perl, v5.10.0 built for MSWin32-x86-multi-thread
(with 5 registered patches, see perl -V for more detail)

 

[Joost Diepenmaat]

The c:/dir is exist.

print -e 'C:/dir/"';
the result is 1 ,why?

Because -e checks if a "file" exists from a POSIX perspective, where
directories and symlinks are files - in other words, it checks if a path
exists. If you want to check if the path exists and is a file (not a
directory, or a symlink to a file), use -f.

print -e 'C:/"';
the result is null

Windows is strange. I would have expected some true value.

 

[Joost Diepenmaat]

Because -e checks if a "file" exists from a POSIX perspective, where
directories and symlinks are files - in other words, it checks if a path
exists. If you want to check if the path exists and is a file (not a
directory, or a symlink to a file), use -f.

^^^^^^^^^^^^^^^^^ - I meant: "symlink to a directory"

 

[mynews]

But i don't have the (file/directory/symlink to a file) " .
Or the " have specially meaning on win32?

 

[RedGrittyBrick]

But i don't have the (file/directory/symlink to a file) " .
Or the " have specially meaning on win32?

Yes, Windows does do strange things with a trailing unbalanced quote mark.

C:\Users\RGB> dir C:\"
Volume in drive C is OS
Volume Serial Number is 49F8-F27B

Directory of C:\

18/09/2006 21:43 24 autoexec.bat
18/09/2006 21:43 10 config.sys
....

I don't have a file, directory or hotlink named " either (so far as I
can see).