XML Transformation question

[Eta]

Hi all,
I need to transform an XML input file throught Java. Use
javax.xml.transform package to do it.
The XSLT file need a PARAM but I don't know how pass its value to the
Transformer object.

Here the code who make the transformation:

Transformer transformer =factory.newTransformer(new StreamSource
("RUBRICA.xslt"));


transformer.transform(new StreamSource("RUBRICA.xml"),new StreamResult
("RUBRICA.txt"));


Its work fine but how can I pass a param value to the XSLT file??

Thanks in advance,

and sorry for my bad english.

Ciao,

Eta

 

[Murray]

Transformer transformer =factory.newTransformer(new StreamSource
("RUBRICA.xslt"));


transformer.transform(new StreamSource("RUBRICA.xml"),new StreamResult
("RUBRICA.txt"));


Its work fine but how can I pass a param value to the XSLT file??

Thanks in advance,

transformer.setParameter("paramName", paramValue);

Then in your XSLT

<xslaram name="paramName"/> or alternatively <xslaram
name="debug">defaultValue</xslaram>

which essentially makes it globally available using $paramName

 

[Eta]

Thank you Murray!

Eta