lauch browser on remote windows mach from linux python?

[gry]

My users work at windows PC's. They run my app on my linux server,
displaying the gtk/pytgk graphics via the hummingbird/exceed X server.
When a user clicks on a URL in my app, I want to lauch mozilla, running
on the PC, with the specified URL. Is there some way to do this?

[sorry, I'm a unix/linux hacker -- no understanding of MS system stuff]

I can imagine a tiny python daemon running on each PC, listening for a
connection on a particular port, and reading a URL from it.
Can it just call os.system('mozilla ...')?
Or do I have to do some .com or .net thing?

I know this sounds like opening a huge security hole in the PC, but
it's MS -- isn't that where holes belong ;-). The daemon could reject
all but appropriate local URL's.

-- George Young

 

[drs]

I want to lauch mozilla, running
on the PC, with the specified URL.

* * *

I can imagine a tiny python daemon running on each PC, listening for a
connection on a particular port, and reading a URL from it.
Can it just call os.system('mozilla ...')?
Or do I have to do some .com or .net thing?

similar to the method you proposed, but using pure python, you might look at
pyro (http://pyro.sourceforge.net).

-d

 

[Dennis Lee Bieber]

I can imagine a tiny python daemon running on each PC, listening for a
connection on a particular port, and reading a URL from it.
Can it just call os.system('mozilla ...')?

On the Windows side -- use os.startfile(URL) and let the OS
bring up the browser configured for that type of URL.

This does imply having the daemon locally...

--

 

[George Kinney]

I can imagine a tiny python daemon running on each PC, listening for a
connection on a particular port, and reading a URL from it.
Can it just call os.system('mozilla ...')?
Or do I have to do some .com or .net thing?

sure, you can do:
os.startfile(someURL)
or:
os.system('start %s' % someURL)

either one will invoke the configured URL handler. (browser or whatever)