__VA_ARGS__

[Russell Shaw]

Hi,

I have a variadic macro:

#define throw(msg, ...) excep_throw(msg, __VA_ARGS__)


If i do: throw("Error", 0), it compiles ok.

If i do: throw("Error"), i get an error:

error: parse error before ')' token


I think it's because without the last parameter, the function is
called as: except_throw("Error", ). How do i get rid of this trailing
comma problem?

I'm using gcc-3.4.4.


void excep_throw(char *msg, ...)
{
...
}

 

[Russell Shaw]

Hi,

I have a variadic macro:

#define throw(msg, ...) excep_throw(msg, __VA_ARGS__)


If i do: throw("Error", 0), it compiles ok.

If i do: throw("Error"), i get an error:

error: parse error before ')' token


I think it's because without the last parameter, the function is
called as: except_throw("Error", ). How do i get rid of this trailing
comma problem?

I'm using gcc-3.4.4.


void excep_throw(char *msg, ...)
{
...
}

Disregard, i figured it out. Always have one mandatory parameter
withing the va-args.

 

[William Ahern]

Hi, ?
I have a variadic macro:

#define throw(msg, ...) excep_throw(msg, __VA_ARGS__)


If i do: throw("Error", 0), it compiles ok.

If i do: throw("Error"), i get an error:

error: parse error before ')' token

I think it's because without the last parameter, the function is
called as: except_throw("Error", ). How do i get rid of this trailing
comma problem?

#define throw(...) excep_throw(__VA_ARGS__)

 

[James Hess]

Hi,

I have a variadic macro:

#define throw(msg, ...) excep_throw(msg, __VA_ARGS__)

Try

#define throw(msg, ...) excep_throw(msg, ##__VA_ARGS__)



-J. Hess

 

[Ben Pfaff]

Try

#define throw(msg, ...) excep_throw(msg, ##__VA_ARGS__)

That solution is specific to GCC.