Background image in XML ..Urgent !!

[Manoj Nair]

I have a XSL file which has the following code for background image. <fo:table-body> <fo:table-row text-align="center"> <fo:table-cell background-image="copy.gif" border-after-style="none" border-before-style="none" border-end-style="none" border-start-style="none" font-size="10pt" text-align="center" padding-start="3pt" padding-end="3pt" padding-before="3pt" padding-after="3pt" display-align="center" border-style="solid" border-width="1pt" border-color="white">

I am running this in weblogic and during runtime the FOP parser always looks for copy.gif in the weblogic directory which is c:\bea\user_projects\mydomain. But I have the gif file in my web application directory c:\xxx\yyy\ where the *.XSD file resides. What should I set the URL to to tell the FOP parser to get the gif file from same directory as where the XSD resides ??

Thanks

 

[Patrick Melo]

What should I set the URL to to tell the FOP parser to get the gif file from same directory as where the XSD resides ??

1. Write an action to pass the path to the sitemap.
[see http://www.db.informatik.uni-kassel.de/Help/xml/cocoon/userdocs/concepts/actions.html]

Context context = ObjectModelHelper.getContext(objectModel); String path = context.getRealPath(request.getServletPath); java.io.File f = new java.io.File(path); if (!f.isDirectory) path = f.getParentFile.getAbsolutePath; sitemapParams.put("path", path);

2. In the transform element of your sitemap add a parameter to pass the path to the xsl. <maparameter name="path" value="{path}" />

3. In your xsl, add a parameter to use the path in your xsl. <xslaram name="path" select="''"/>

background-image="url('{$path}/copy.gif')"

Hope this helps,
Patrick