block.call

R

Ruby Newbee

Hello gurus,

please see the code below, why passing a block to a function then call
block.call in the function will get success, but run block.call out of
a function will get failed?


irb(main):023:0* def myhi(&block)
irb(main):024:1> block.call
irb(main):025:1> end
=> nil

irb(main):026:0> myhi { puts "hi welcome" }
hi welcome
=> nil

irb(main):027:0> { puts "hi welcome" }.call
SyntaxError: (irb):27: syntax error, unexpected tSTRING_BEG, expecting
keyword_do or '{' or '('
{ puts "hi welcome" }.call
^
(irb):27: syntax error, unexpected '}', expecting $end
{ puts "hi welcome" }.call
^
from /usr/bin/irb:12:in `<main>'
 
R

Robert Klemme

Hello gurus,

please see the code below, why passing a block to a function then call
block.call in the function will get success, but run block.call out of
a function will get failed?


irb(main):023:0* def myhi(&block)
irb(main):024:1> block.call
irb(main):025:1> end
=> nil

irb(main):026:0> myhi { puts "hi welcome" }
hi welcome
=> nil

irb(main):027:0> { puts "hi welcome" }.call
SyntaxError: (irb):27: syntax error, unexpected tSTRING_BEG, expecting
keyword_do or '{' or '('
{ puts "hi welcome" }.call
^
(irb):27: syntax error, unexpected '}', expecting $end
{ puts "hi welcome" }.call
^
from /usr/bin/irb:12:in `<main>'

Because, as the error message says, this is not valid Ruby syntax. You
can use "lambda" or "proc" instead:

irb(main):001:0> lambda { puts "hi" }.call
hi
=> nil
irb(main):002:0>

But this is really useless, i.e. in that case you should simply do "puts
'hi'". The lambda notation really only makes sense if you want to store
the block away for later usage. Note, that there is also this syntax
(in case you want to structure your code):

begin
puts 'hi'
end


Kind regards

robert
 
J

Jeff Peng

Ruby Newbee:
thanks.
but why in the function block.call can be executed?


An incoming code block will be converted into a Proc object and bound
^^^^^^^^^^^^^^^^^^^^^^^^^^^^
to the block variable. You can pass it around to other methods, call it
directlyusing call,or yield to it as though you’d never bound it to a
variable at all.
 

Ask a Question

Want to reply to this thread or ask your own question?

You'll need to choose a username for the site, which only take a couple of moments. After that, you can post your question and our members will help you out.

Ask a Question

Members online

Forum statistics

Threads
473,744
Messages
2,569,484
Members
44,906
Latest member
SkinfixSkintag

Latest Threads

Top