C program

[satyamshapam]

Evaluate p+=++p+p++ initially if p=10

 

[CodeMonkeyJ]

First, we evaluate the right side. Pre-increment and post-increment have the highest priority there and are the same priority, so we go left to right. Let's put some parenthesis around those to make it a bit easier to read and then evaluate them. After the two increments, p will be 12.

p += ++p + p++
p += (++p) + (p++)
p += (11) + (12)
p += 23
p = 12 + 23
p = 35

To verify, you can simply compile and run it.

#include <stdio.h>

int main(){
        int p = 10;
        p += ++p + p++;
        printf("%d\n", p); // 35
        return 0;
}