Calling base class constructor?

[Fedor Semenov]

How can I call a base class' constructor from a derived class. Suppose I
have:
class Button // Base class
{
public:
Button(void)
{
// Register classes, create the button, etc.
}
};

class MyButton : public Button // Derived class
{
public:
MyButton(void)
{
// Customize title, size, etc.
// How do I call Button's (base class) constructor here?
}
};

 

[Jerry Coffin]

How can I call a base class' constructor from a derived class. Suppose I
have:
class Button // Base class
{
public:
Button(void)
{
// Register classes, create the button, etc.
}
};

class MyButton : public Button // Derived class
{
public:
MyButton(void)
{
// Customize title, size, etc.
// How do I call Button's (base class) constructor here?
}
};

This is probably in the FAQ somewhere. Given that your
base class ctor doesn't take any parameters, it'll be
called entirely automatically in the process of creating
an object.

If your base class ctor takes parameters, you can do
something like this to pass the correct parameters:

struct base {
base(int y);
};

struct derived : public base {
derived() : base(1) {}
};