Char to char*?

[Tom Zych]

Using a function call of any sort where a simple array insert takes care
of the problem seems somewhat overdone.

The array insert wouldn't be so simple. You have to use strlen to
find the right place. Then you have to copy c. Then you have to
terminate line again. This one call does all that.

 

[Default User]

The array insert wouldn't be so simple. You have to use strlen to
find the right place. Then you have to copy c. Then you have to
terminate line again. This one call does all that.

Perhaps so.




Brian Rodenborn

 

[Jack Klein]

int main()
{
char str1[] = "Your grade is ";
char str2[] = "A";

char str3[1];

strcpy(str3, strcat(str1, str2));

printf("%s\n", str3);

return 0;
}

strcat changes dest in place. str1 can't be changed. str3 is only
one byte long.

#include <stdio.h>
#include <string.h>

int main(void) {
char line[100];
char *s1 = "Happy Day";
char c = 's';
strcpy(line,s1);
strncat(line, &c, 1);
printf("%s\n", line);
return 0;
}

Undefined behavior.

--
Jack Klein
Home: http://JK-Technology.Com
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[Jack Klein]

Steve Zimmerman wrote:

int main()
{
char str1[] = "Your grade is ";
char str2[] = "A";

char str3[1];

strcpy(str3, strcat(str1, str2));

printf("%s\n", str3);

return 0;
}

strcat changes dest in place. str1 can't be changed. str3 is only
one byte long.

#include <stdio.h>
#include <string.h>

int main(void) {
char line[100];
char *s1 = "Happy Day";
char c = 's';
strcpy(line,s1);
strncat(line, &c, 1);
printf("%s\n", line);
return 0;
}

Undefined behavior.

Sorry, my bad, no it's not.

--
Jack Klein
Home: http://JK-Technology.Com
FAQs for
comp.lang.c http://www.eskimo.com/~scs/C-faq/top.html
comp.lang.c++ http://www.parashift.com/c++-faq-lite/
alt.comp.lang.learn.c-c++ ftp://snurse-l.org/pub/acllc-c++/faq

 

[Peter Shaggy Haywood]

Groovy hepcat Sona was jivin' on Wed, 10 Sep 2003 06:44:29 +1000 in
comp.lang.c.
Char to char*?'s a cool scene! Dig it!

How is it possible to convert a char to char* in C? I'm trying to append

Don't. There's a better way.

a char to the end of a char* using the strcat function.. the following

Try this:

char *charcat(char *s, char c)
{
size_t len = strlen(s);

s[len] = c;
s[len + 1] = '\0';

return s;
}

--

Dig the even newer still, yet more improved, sig!

http://alphalink.com.au/~phaywood/
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