Disabling a function definition

[er]

Hi All,
Here's an dilemma:

I used to have some code like this:

template<int i>
void f(){};

but now I found out how to do away with the template parameter:

void f(){};

However, I don't want to rewrite the old code I have that depends on
the first definition, while being able to use the new definition in
the new code. I don't think I can have it both ways, but perhaps
someone else has thought of this before me.

 

[Victor Bazarov]

Here's an dilemma:

I used to have some code like this:

template<int i>
void f(){};

but now I found out how to do away with the template parameter:

void f(){};

However, I don't want to rewrite the old code I have that depends on
the first definition, while being able to use the new definition in
the new code. I don't think I can have it both ways, but perhaps
someone else has thought of this before me.

Have you tried just having them both? If yes, what happened? If not,
why not?

V

 

[er]

Have you tried just having them both?  If yes, what happened?  If not,
why not?

Good thing I stopped by, and thank you!