Double Pointer

[Soko]

Hi,

I have got confused with pointer arithmetic.

char **p;
printf("%d\n",p++);

Result is 4.

Can anyone please explain to me in detail how so.

Regards
Soko

 

[abhijeet.pathak]

First of all, you should not use a pointer unless you initialize it.
In the given code, you have just declared the pointer but not initialized it.
So when you'll access p (either as 'p' or 'p++') you will get memory location that is pointed by p, which in this case is random value...