Full splitting of a file's pathname

[tac-tics]

I know about os.path.split(), but Is there any standard function for
"fully" splitting a file's pathname? A function that is the opposite of
the os.path.join() function? For example:
['.', 'foo', 'bar', 'moo', 'lar', 'myfile.txt']

In the meanwhile, I'll do this by hand. I'm just curious if there is a
standard way to do this.

 

[BartlebyScrivener]

I don't know if it's "standard," but why not just:

dir = './foo/bar/moo/lar/myfile.txt'
dir.split('/')

['.', 'foo', 'bar', 'moo', 'lar', 'myfile.txt']

rd

 

[Iain King]

I know about os.path.split(), but Is there any standard function for
"fully" splitting a file's pathname? A function that is the opposite of
the os.path.join() function? For example:
['.', 'foo', 'bar', 'moo', 'lar', 'myfile.txt']

In the meanwhile, I'll do this by hand. I'm just curious if there is a
standard way to do this.

Simple function using os.path.split (so it should be fairly
compatible):

def split(path):
h,t = os.path.split(path)
if h == path:
return [h]
else:
return split(h) + [t]

You could throw in os.path.splitdrive and os.path.splitunc, if you
wanted to be really complete.

Iain

 

[Simon Forman]

I don't know if it's "standard," but why not just:

dir = './foo/bar/moo/lar/myfile.txt'
dir.split('/')

['.', 'foo', 'bar', 'moo', 'lar', 'myfile.txt']

rd

There's also os.path.sep, from the docs: "The character used by the
operating system to separate pathname components."
But a recursive function like the one Iain King posted is likely the
best way to go.

~Simon