function reference and ->

[toylet]

my $rf = \&{"afunction"};

I could call the function by $rf->(0) or &{$rf};

Is there a $rf->(1)?

Which chapter in perldoc should I read to learn more on this infix
thing? perlop didn't talk much.

 

[Tassilo v. Parseval]

Also sprach toylet:

my $rf = \&{"afunction"};

I could call the function by $rf->(0) or &{$rf};

Is there a $rf->(1)?

There is even a $rf->(42). They don't mean the same thing however. What
you put into the parens is passed as argument to the function referenced
by $rf. If you don't want to pass anything, call $rf->().

Which chapter in perldoc should I read to learn more on this infix
thing? perlop didn't talk much.

Probably perlref.pod.

Tassilo

 

[pkent]

my $rf = \&{"afunction"};

as the other poster says, you'd call this as $rf->() or $rf->($arg) or
$rf->(@args) - although I'd personally write it as:

my $rf = \&afunction;

sub afunction {
# blah
}

for what it's worth

P