hexadecimal addition

[king]

I have a register lets say F0200088 (hexadecimal number)

And I want to jump 7 dwords so that I will reach F02000B0 (i.e 88 will
become B0 in hex)

How can I do hexa addition in perl to get this value of F02000B0.

I tried this but not getting it.

sprintf "%X\n",oct("0xF0200088")+oct("0x08");

 

[Jürgen Exner]

I have a register lets say F0200088 (hexadecimal number)

And I want to jump 7 dwords so that I will reach F02000B0 (i.e 88 will
become B0 in hex)

How can I do hexa addition in perl to get this value of F02000B0.

sprintf "%X\n",oct("0xF0200088")+oct("0x08");

But 0xF0200088 + 0x08 is 0xF0200090 and not 0xF02000B0. Are you adding the
wrong numbers?\

jue

 

[Doug Miller]

I have a register lets say F0200088 (hexadecimal number)

And I want to jump 7 dwords so that I will reach F02000B0 (i.e 88 will
become B0 in hex)

On what system is a dword 5.57143 bytes long?

0xF02000B0 - 0xF0200088 = 0x28 = decimal 40

How can I do hexa addition in perl to get this value of F02000B0.

I tried this but not getting it.

sprintf "%X\n",oct("0xF0200088")+oct("0x08");

0xF0200088 + 0x8 = 0xF0200090

 

[Doug Miller]

On what system is a dword 5.57143 bytes long?

Oops, too many fives -- meant 5.7143