How to get a file as a resource

[GIMME]

The following lines exist in a JSP ...

String sRealPath = session.getServletContext().getRealPath("/"); /*1*/
String sXSLFile = sRealPath + "/xsl/xl.xsl" /*2*/
Reader r = new FileReader( new File(sXSLFile) ) ; /*3*/
StreamSource ss = new StreamSource(r); /*4*/

transformer = TransformerFactory.newInstance().newTransformer( ss ) ;

How would lines 1,2,3 and 4 be changed so that the xl.xsl file
is fetched as a resource instead of from the file system?

Thanks

 

[Jacob]

The following lines exist in a JSP ...

String sRealPath = session.getServletContext().getRealPath("/"); /*1*/
String sXSLFile = sRealPath + "/xsl/xl.xsl" /*2*/
Reader r = new FileReader( new File(sXSLFile) ) ; /*3*/
StreamSource ss = new StreamSource(r); /*4*/

transformer = TransformerFactory.newInstance().newTransformer( ss ) ;

How would lines 1,2,3 and 4 be changed so that the xl.xsl file
is fetched as a resource instead of from the file system?

Something like:

String filePath = "/com/company/dir/xl.xsl";
InputStream stream = getClass().getResourceAsStream (filePath);
BufferedReader reader = new BufferedReader (new InputStreamReader (stream));
StreamSource source = new StreamSource (reader);

Don't forget the initial "/" in the path.
It is a common source of error.