Inputting HH:MM:SS format

[crystal twix]

I'm trying to ask the user for a time in the format HH:MM:SS, and I
was wondering what the best way would be to input those values into a
struct that looks like:

struct time {
int hour;
int min;
int sec;
};

Thanks!

 

[Maxim Yegorushkin]

I'm trying to ask the user for a time in the format HH:MM:SS, and I
was wondering what the best way would be to input those values into a
struct that looks like:

struct time {
int hour;
int min;
int sec;
};

For parsing there is strftime() function:
http://www.cplusplus.com/reference/clibrary/ctime/strftime/

 

[Maxim Yegorushkin]

For parsing there is strftime() function:
http://www.cplusplus.com/reference/clibrary/ctime/strftime/

Oops, I meant strptime():
http://www.opengroup.org/onlinepubs/009695399/functions/strptime.html

 

[crystal twix]

Oops, I meant strptime():http://www.opengroup.org/onlinepubs/009695399/functions/strptime.html

Ok, I read the reference and tried going over the example. Would I do
something like this?

struct Time {
int hours, minutes, seconds;
};

const int length = 8;

int main() {

char time[length];
char *time;

cout << "Enter time:";
cin >> time;
Time timeStruct = strptime(time, "%H %M %S", &time);
}

Thanks!

 

[James Kanze]

On 07/11/09 22:33, Maxim Yegorushkin wrote:

Oops, I meant
strptime():http://www.opengroup.org/onlinepubs/009695399/functions/strptime.html

Not in C++. That's a Posix extension, so if you're concerned
with portability, you can't use it.

There are several solutions to what he wants to do, depending on
the context and how flexible he wants to be with regards to the
input (exactly two digits for the hour, or one or two digits,
etc.). Basically, however, I'd start by defining a
std::istream& operator>>(std::istream& source, time& dest)
function, using sgetc on the input to determine if the next
character was what I wanted. Depending on how flexible I wanted
to be, I might just read exactly eight characters, validate it
with a regular expression, then use an istringstream to convert
the three numbers; or I'd input a number, check for and extract
the ':', input another number, check for and extract the ':',
and input the third number.