Insert current timestamp/date from XSLT stylesheet into a XML document ???

[Michael Hertz]

I am performing a XSLT stylesheet on a XML document and produce a new XML document. How can I insert in this new XML stylesheet a tag

<currtime>..."the current date/time"....</currtime>

where "the current date/time" above is replaced by the real current time (e.g.
12th Sep 2004 09:23:78

Michael

 

[Thomas Sommer]

Am Mon, 04 Oct 2004 07:41:38 +0200 schrieb Michael Hertz:

<currtime>..."the current date/time"....</currtime>

With xsltproc I use:
--stringparam date="`date stylesheet.xsl`"

Then you have to a xslaram where the value is the momentary date

Thomas

 

[Mukul Gandhi]

Its possible with extension functions..

Please try this..
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:datetime="http://exslt.org/dates-and-times" exclude-result-prefixes="datetime">

<xsl:template match="/">
<currtime>
<xsl:value-of select="datetime:dateTime" />
</currtime>
</xsl:template>

</xsl:stylesheet>

(Tested with Xalan-J 2.6.0)

Regards,
Mukul

 

[Martin Honnen]

I am performing a XSLT stylesheet on a XML document and produce a new XML document. How can I insert in this new XML stylesheet a tag

<currtime>..."the current date/time"....</currtime>

where "the current date/time" above is replaced by the real current time (e.g.
12th Sep 2004 09:23:78

With XSLT 1.0/XPath 1.0 you need to define a global parameter e.g. <xslaram name="now" /> and then use processor specific means to set that parameter before you run the transformation.