new byte always initialized to 0?

[34stunts]

Consider the following code:
byte b[] = new byte[34];
for (int x = 0; x < b.length; x++)
{
System.out.println((int) b[x] );
}

Java compiles it and runs it. This prints a bunch of "0".

So my question is this correct code? Or should/must I have a loop to
assign it to 0. Is it a rule that a newly created byte is 0 or is this
merly a coincidence?

-
Fred

 

[34stunts]

Sorry for the spam :-(

 

[Andrew Thompson]

Sorry for the spam :-(

Posting a single post 3 times to one group may be overkill,
but it is not spam. I think the term is 'reposting'.

The term spam generally refers to advertising of products.

Noting that you are posting through Google groups, I
think I can guess the basic reason ..the Google groups
server told you it 'could not complete that action' (or
similar words)?

A tip is to keep a second browser open, pointing to the group.
After posting, or when you get a message like that - wait
a few seconds and refresh the page showing the group
'titles' list - the podt will often make it through - depsite
what the server claimed.

(I am not sure on your technical query - I'll leave that for
the JLS gurus)

Andrew T.

 

[Ian Shef]

(e-mail address removed) wrote in @b28g2000cwb.googlegroups.com:

Consider the following code:
byte b[] = new byte[34];
for (int x = 0; x < b.length; x++)
{
System.out.println((int) b[x] );
}

Java compiles it and runs it. This prints a bunch of "0".

So my question is this correct code? Or should/must I have a loop to
assign it to 0. Is it a rule that a newly created byte is 0 or is this
merly a coincidence?

The JLS (3rd edition) at paragraph 4.12.5 says:

4.12.5 Initial Value of Variables

Every variable in a program must have a value before its value is used:
• Each class variable, instance variable, or array component is
initialized with a default value when it is created (§15.9, §15.10):
 For type byte, the default value is zero, that is,
the value of (byte)0.

.... so the answer is that this is a rule and not a coincidence.