numbering across different elements

[Mike Dickens]

hi,
suppose i have:

<a>
<b i="Y" j="aaaa"/>
<c i="N" j="bbbb"/>
<d i="Y" j="cccc"/>
<e i="N" j="dddd"/>
<f i="N" j="eeee"/>
<g i="Y" j="ffff"/>
</a>

and i want to extract the elements where i="Y" such that i get something like <x> <y>1. aaaa</y> <y>2. cccc</y> <y>3. gggg</y> </x>

how would i get the numbering to work across the different elements?

thanks,
mike

 

[Richard Tobin]

and i want to extract the elements where i="Y" such that i get something like <x> <y>1. aaaa</y> <y>2. cccc</y> <y>3. gggg</y> </x>

how would i get the numbering to work across the different elements?

Use xsl:number with the "count" attribute to specify which elements are counted.

-- Richard

 

[Jeff Kish]

hi,
suppose i have:

<a>
<b i="Y" j="aaaa"/>
<c i="N" j="bbbb"/>
<d i="Y" j="cccc"/>
<e i="N" j="dddd"/>
<f i="N" j="eeee"/>
<g i="Y" j="ffff"/>
</a>

and i want to extract the elements where i="Y" such that i get something like <x> <y>1. aaaa</y> <y>2. cccc</y> <y>3. gggg</y> </x>

how would i get the numbering to work across the different elements?

thanks,
mike

mmmm.. you just want to enumerate all of your elements? What technology is at your disposal?

In XQuery, using books.xml,
this query:

for $t at $i in document("books.xml")//*[@year="1994"]
return <Response>{$i, name($t), string($t/@year)}</Response>

returns this data:

<Response>1 book 1994</Response>

Here is books.xml (from katz_c01.pdf tutorial I found via google at http://www.datadirect.com/news/whatsnew/xquerybook/index.ssp) <bib> <book year="1994">a1994 <title>TCP/IP Illustrated</title> <author> <last>Stevens</last> <first>W.</first> </author> <publisher>Addison-Wesley</publisher> <price>65.95</price> </book> <book year="1992">a1992<title>Advanced Programming in the UNIX Environment</title> <author> <last>Stevens</last> <first>W.</first> </author> <publisher>Addison-Wesley</publisher> <price>65.95</price> </book> <book year="2000">a2000<title>Data on the Web</title> <author> <last>Abiteboul</last> <first>Serge</first> </author> <author> <last>Buneman</last> <first>Peter</first> </author> <author> <last>Suciu</last> <first>Dan</first> </author> <publisher>Morgan Kaufmann Publishers</publisher> <price>65.95</price> </book> <book year="1999">a1999<title>The Economics of Technology and Content for Digital TV</title> <editor> <last>Gerbarg</last> <first>Darcy</first> <affiliation>CITI</affiliation> </editor> <publisher>Kluwer Academic Publishers</publisher> <price>129.95</price> </book> </bib>

Jeff Kish

 

[=?ISO-8859-1?Q?J=FCrgen_Kahrs?=]

<a>
<b i="Y" j="aaaa"/>
<c i="N" j="bbbb"/>
<d i="Y" j="cccc"/>
<e i="N" j="dddd"/>
<f i="N" j="eeee"/>
<g i="Y" j="ffff"/>
</a>

and i want to extract the elements where i="Y" such that i get something like

For the sake of comparison, here is a solution in XMLgawk:

BEGIN {
XMLMODE=1
print "<x>"
}

XMLSTARTELEM {
if (XMLATTR["i"] == "Y")
print " <y>" ++n ". " XMLATTR["j"] "</y>"
}

END { print "</x>" }

I tested it and it produced:

<x>
<y>1. aaaa</y>
<y>2. cccc</y>
<y>3. ffff</y>

how would i get the numbering to work across the different elements?

You probably mean how to make sure that nodes
at all nesting levels are treated in the same
way. In XMLgawk this is no problem because the
interpreter traverses all nodes anyway.

 

[Mike Dickens]

whoops,
i forgot to mention. i need to do this as an xsl transform. i am thinking <xsl:number> is probably the way i want to go, but am unsure as to how to go about it. all the examples i can find refer to elements of the same type, not amalgamating different types as i want to do here.

mike.

 

[=?ISO-8859-1?Q?J=FCrgen_Kahrs?=]

Notice this one ^^^^

I think you have an error in 3.

The script that I posted yesterday found this error.

 

[Jürgen Kahrs]

Mike Dickens wrote:

><a>
> <b i="Y" j="aaaa"/>
> <c i="N" j="bbbb"/>
> <d i="Y" j="cccc"/>
> <e i="N" j="dddd"/>
> <f i="N" j="eeee"/>
> <g i="Y" j="ffff"/>

Notice this one ^^^^

></a>
>
>and i want to extract the elements where i="Y" such that i get something like
><x>
> <y>1. aaaa</y>
> <y>2. cccc</y>
> <y>3. gggg</y>

I think you have an error in 3.

></x>
>

The script that I posted yesterday found this error.

 

[Marrow (2)]

Hi Mike,

Try something like...

<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xslutput method="xml"/>

<xsl:template match="/a">
<xsl:copy>
<xsl:apply-templates select="*[@i = 'Y']"/>
</xsl:copy>
</xsl:template>

<xsl:template match="*">
<y>
<xsl:value-of select="position"/>
<xsl:text>. </xsl:text>
<xsl:value-of select="@j"/>
</y>
</xsl:template>
</xsl:stylesheet>

HTH
Marrow
http://www.marrowsoft.com - home of Xselerator (XSLT IDE and debugger) http://www.topxml.com/Xselerator

 

[Richard Tobin]

i forgot to mention. i need to do this as an xsl transform. i am thinking <xsl:number> is probably the way i want to go, but am unsure as to how to go about it.

The count attribute is a pattern which matches the elements that should be counted. So you just need something like:

<xsl:template match="*[@i = 'Y']">
<y>
<xsl:number count="*[@i = 'Y']"/>
<xsl:text>. </xsl:text>
<xsl:value-of select="@j"/>
</y>
</xsl:template>

-- Richard

 

[Mike Dickens]

i think i simplified my example to much. a more accurate file would be:
<a>
<b a="Y" m="aaaa"/>
<c b="N" n="bbbb"/>
<d c="Y" o="cccc"/>
<e d="N" p="dddd"/>
<f e="N" q="eeee"/>
<g f="Y" r="ffff"/>

this means the is no commonality in the source elements i'm massaging into a numbered list in the result elements.

in the end i just persuaded the powers that be to do it differently

thanks for the help tho'
mike.

i forgot to mention. i need to do this as an xsl transform. i am thinking <xsl:number> is probably the way i want to go, but am unsure as to how to go about it.

The count attribute is a pattern which matches the elements that should be counted. So you just need something like:

<xsl:template match="*[@i = 'Y']">
<y>
<xsl:number count="*[@i = 'Y']"/>
<xsl:text>. </xsl:text>
<xsl:value-of select="@j"/>
</y>
</xsl:template>

-- Richard

 

[Richard Tobin]

i think i simplified my example to much. a more accurate file would be:

There is no problem with this. So long as the pattern
in the count attribute of the sort matches the same nodes as the match attribute of the template, it will count those elements.

If you are listing elements that have any attribute equal to Y, just use @*='Y' instead of @i='Y'.

-- Richard

 

[William Park]

hi,
suppose i have:

<a>
<b i="Y" j="aaaa"/>
<c i="N" j="bbbb"/>
<d i="Y" j="cccc"/>
<e i="N" j="dddd"/>
<f i="N" j="eeee"/>
<g i="Y" j="ffff"/>
</a>

and i want to extract the elements where i="Y" such that i get something like <x> <y>1. aaaa</y> <y>2. cccc</y> <y>3. gggg</y> </x>

how would i get the numbering to work across the different elements?

If you can compile a Bash shell, then

start {
local "$@" # b i=Y j=aaaa
[ "$i" = Y ] && echo $((++count)). $j
}
xml -s start "`< file.xml`"

will print

1. aaaa
2. cccc
3. ffff

Ref:
http://freshmeat.net/projects/bashdiff/