parsing a file name

[CSUIDL PROGRAMMEr]

I have a filename
cairo-2.3.4.src.rpm
Is there any way i can only get 2.3.4 from this file name
thanks

 

[Chris Mellon]

I have a filename
cairo-2.3.4.src.rpm
Is there any way i can only get 2.3.4 from this file name
thanks

I'm trying to think of a good reason to extract the version from the
filename instead of using RPM to get the real version from the
metadata and I can't come up with one.

 

[Paul Boddie]

I'm trying to think of a good reason to extract the version from the
filename instead of using RPM to get the real version from the
metadata and I can't come up with one.

The inquirer doesn't have any RPM handling tools installed/available or
is dealing with a lot of versioned filenames which might be a selection
of different, arbitrary formats.

Try harder! ;-)

Paul

 

[Chris Mellon]

The inquirer doesn't have any RPM handling tools installed/available or
is dealing with a lot of versioned filenames which might be a selection
of different, arbitrary formats.

Try harder! ;-)

Paul

Well, the answer to the first is "get some", so that's not a good
reason. And the second would mean that they asked a question on c.l.p
without giving all the background information on the task they were
doing, and we know that never happens.

 

[Roberto Bonvallet]

I have a filename
cairo-2.3.4.src.rpm
Is there any way i can only get 2.3.4 from this file name

>>> a = "cairo-2.3.4.src.rpm"
>>> import re
>>> re.compile(r"\d+([.]\d+)*").search(a).group(0) '2.3.4'
>>> a.split("-")[-1][:-len(".src.rpm")] '2.3.4'
>>> ".".join(map(str, range(2, 5)))

'2.3.4'