pass by value or pass by address?

[Vols]

void f (char *a)
{
a++;
}

int main (void)
{
char a[] = "abc";// or char *a = "abc";
f (a);
puts (a);
return 0;
}

Looks it is 'pass by address'. The result is 'abc' instead of 'bc'. So
actually it is 'pass by value'.
What happened? thanks.

Vol

 

[Ian Collins]

void f (char *a)
{
a++;
}

int main (void)
{
char a[] = "abc";// or char *a = "abc";
f (a);
puts (a);
return 0;
}

Looks it is 'pass by address'. The result is 'abc' instead of 'bc'. So
actually it is 'pass by value'.
What happened? thanks.

It's pass by value. You are passing the value of the pointer a.

 

[Vols]

Then if I want to output 'bc' instead of 'abc', how to write f()?
Thanks.
Vol.

void f (char *a)
{
a++;
}

int main (void)
{
char a[] = "abc";// or char *a = "abc";
f (a);
puts (a);
return 0;
}

Looks it is 'pass by address'. The result is 'abc' instead of 'bc'. So
actually it is 'pass by value'.
What happened? thanks.

It's pass by value. You are passing the value of the pointer a.

 

[Ian Collins]

Vols wrote:

{please don't top-post]

void f (char *a)
{
a++;
}
int main (void)
{
char a[] = "abc";// or char *a = "abc";
f (a);
puts (a);
return 0;
}
Looks it is 'pass by address'. The result is 'abc' instead of 'bc'. So
actually it is 'pass by value'.
What happened? thanks.

It's pass by value. You are passing the value of the pointer a.

Then if I want to output 'bc' instead of 'abc', how to write f()?

[or quote signatures]

void f( char*& a)
{
a++;
}