E
Ellie
In my program the user clicks on a link and using the window.open
function, opens a new window.
I pass a url to the new window like this:
<a href="#"
onClick="window.open('../quotescreenwindow.php?enroll_id=enrollwindowprime.php',
'WindowC', 'width=750,height=800,scrollbars=yes');">
In the new window that just opened called quotescreenwindow.php, I
have a button that when clicked, should open yet another window called
enrollwindowprime.php (this is the variable I am passing after the
question mark).
What I cannot do, is to grab this variable that I am passing to the
first window I open and use its content to open the next window.
I am not very experienced and have been piecing this together from
various web sites.
To simplify all of this:
Screen A Opens Popup Window B and passes it a variable with a url
inside of it.
Popup Window B wants to use the variable with the url to open Pop Up
Window C.
I would really appreciate some help.
function, opens a new window.
I pass a url to the new window like this:
<a href="#"
onClick="window.open('../quotescreenwindow.php?enroll_id=enrollwindowprime.php',
'WindowC', 'width=750,height=800,scrollbars=yes');">
In the new window that just opened called quotescreenwindow.php, I
have a button that when clicked, should open yet another window called
enrollwindowprime.php (this is the variable I am passing after the
question mark).
What I cannot do, is to grab this variable that I am passing to the
first window I open and use its content to open the next window.
I am not very experienced and have been piecing this together from
various web sites.
To simplify all of this:
Screen A Opens Popup Window B and passes it a variable with a url
inside of it.
Popup Window B wants to use the variable with the url to open Pop Up
Window C.
I would really appreciate some help.