[python] pass the name of args

[macm]

Hi Folks

def myDef(x)
doSomething x
result = x.????
return coolThings
---------------------------------

WhatYourName = ('python','is','cool')

myDef(WhatYourName)

so what I am looking for in myDef

result = WhatYourName

----------------------------------
again :
IhaveOtherName = ('some','thing')

myDef(IhaveOtherName)

so what I am looking for in myDef

result = IhaveOtherName

----------------------------------

Is it possible with python?

Regards

macm

 

[Chris Rebert]

Hi Folks

def myDef(x)
       doSomething x
       result = x.????
       return coolThings
---------------------------------

WhatYourName = ('python','is','cool')

myDef(WhatYourName)

so what I am looking for in myDef

       result = WhatYourName

----------------------------------
again :
IhaveOtherName = ('some','thing')

myDef(IhaveOtherName)

so what I am looking for in myDef

       result = IhaveOtherName

Not without very evil black-magic hackery. Explain /why/ you want this
magic myDef() and someone will probably be able to suggest a better,
alternative approach.

Cheers,
Chris

 

[Terry Reedy]

On 6/4/2010 7:32 AM, macm wrote:

A few types of objects have definition names (.__name__ attribute). All
have 0 to many namespace names. If you want to pass an attribute name,
pass it -- as a string.

def myDef(x)
doSomething x
result = x.????
return coolThings

def f(x. x_attr_name):
...
res = getattr(x, x__attr_name)
...

Terry Jan Reedy