random record with SELECT TOP does NOT work

Discussion in 'ASP General' started by Jimmy, Sep 9, 2006.

  1. Jimmy

    Jimmy Guest

    thanks to everyone that helped, unfortunately the code samples people gave me don't work. here is what i have so far:

    <%
    Dim oConn, oRS, randNum
    Randomize()
    randNum = (CInt(1000 * Rnd) + 1) * -1
    Set oConn=Server.CreateObject("ADODB.Connection")
    Set oRS=Server.CreateObject("ADODB.recordset")
    oConn.Provider="Microsoft.Jet.OLEDB.4.0"
    oConn.Open Server.MapPath("temp.mdb")

    oRS.Open "SELECT TOP 1 EMAIL_ADDRESS, r = Rnd(" & randNum & ") FROM TABLE1 ORDER BY r", oConn, adOpenStatic, adLockReadOnly

    Response.Write oRS("EMAIL_ADDRESS")

    oRS.close
    oConn.close
    Set oConn = nothing
    Set oRS = nothing
    %>

    this gives the error: "No value given for one or more required parameters".

    what i would really LOVE is for someone to fill in whatever required parameter im missing, but more important i would like to understand whats going on. there are people who go through life dumb and happy once something "works", but i need to understand how and why its working. even if this code did work, im confused with the SELECT statement (no, i dont have much SQL experience aside from basic queries). what is the "r = Rnd" line doing in the middle of the querie? how am i ordering by r?? also, i dont have an indexed, primary "ID" field in this databae. is that ok for this code to work?

    thank you for your help
     
    Jimmy, Sep 9, 2006
    #1
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  2. oRS.Open "SELECT TOP 1 EMAIL_ADDRESS, r = Rnd(" & randNum & ") FROM
    Do you have adovbs.inc included? Otherwise, where are adOpenStatic and
    adLockReadyOnly defined?

    How about

    Set oRS = oConn.Execute("SELECT ... ORDER BY r")
    It's generating a new random number within Access, seeded by the one you
    created in the ASP code.
    You're applying a random number to each row. TOP 1 ... ORDER BY r will give
    you whatever row happened to get the lowest random number. If you don't use
    ORDER BY, then you will likely get the same row over and over again.

    A
     
    Aaron Bertrand [SQL Server MVP], Sep 9, 2006
    #2
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  3. Jimmy

    Jimmy Guest

    ok so...

    is there a difference in the way you open the recordset, with the Execute
    statement and the way i do it with oRS.Open? will they both accomplish the
    same thing for the purpose of this piece of code?

    yes i do include adovbs.inc

    and im still confused.... what is wrong with the statement as i have it
    right here:

    oRS.Open "SELECT TOP 1 EMAIL_ADDRESS, r = Rnd(" & randNum & ") FROM TABLE1
    ORDER BY r", oConn, adOpenStatic, adLockReadOnly

    it seems like just what youre doing, but it doesnt work.
     
    Jimmy, Sep 9, 2006
    #3
  4. Jimmy

    Jimmy Guest

    that was MY question.

    and i still dont have this working :(

    anyone?


     
    Jimmy, Sep 10, 2006
    #4
  5. Jimmy

    Evertjan. Guest

    Jimmy wrote on 10 sep 2006 in microsoft.public.inetserver.asp.general:
    No, it hat true?
    Don't you know that topposting is frowned upon by many?
    Because I like topposting.
    Why don't you change to a more aggreable way of posting?
    Because I toppost.
    Why cann't others easily follow your thread?
     
    Evertjan., Sep 10, 2006
    #5
  6. Jimmy

    Guest Guest

    what the hell are you talking about?



     
    Guest, Sep 10, 2006
    #6
  7. Jimmy

    Evertjan. Guest

    wrote on 10 sep 2006 in microsoft.public.inetserver.asp.general:

    [topposting corrected]
    Please reread, and be polite, hgive a name.
     
    Evertjan., Sep 10, 2006
    #7
  8. Did you mean:-

    oRS.Open "SELECT TOP 1 EMAIL_ADDRESS, Rnd(" & randNum & ") As r FROM TABLE1
    ORDER BY r", oConn, adOpenStatic, adLockReadOnly

    ??
     
    Anthony Jones, Sep 11, 2006
    #8
  9. You are not allowed to order by a column alias in JetSQL. However, you can
    order by the ordinal position of a column:
     
    Bob Barrows [MVP], Sep 11, 2006
    #9
  10. You see this is why I don't answer Jet based questions there are always
    nuances I miss. Should've stuck to my usual policy ;)
     
    Anthony Jones, Sep 11, 2006
    #10
  11. Jimmy

    Evertjan. Guest

    Bob Barrows [MVP] wrote on 11 sep 2006 in
    microsoft.public.inetserver.asp.general:
    Regarding JetSQL, Bob, do you mean that:

    "SELECT * FROM TABLE1 ORDER BY 0"

    orders by the first field in the database, as set up in Access,
    and

    "SELECT p,q,r FROM TABLE1 ORDER BY 0"

    orders by field p, even if p stands 3rd in the Access setup order?
     
    Evertjan., Sep 11, 2006
    #11
  12. Jimmy

    Jimmy Guest

    i wish so much that someone could make sense of this and make it work...

    here is the query i have, which many people from this group have copied and
    pasted from a website where i also found the query, and it does not work:

    "SELECT TOP 1 EMAIL_ADDRESS, r = Rnd(" & randNum & ") FROM TBL_SECRETS ORDER
    BY r"

    can anyone see why this doesnt work and possibly make it work?
     
    Jimmy, Sep 11, 2006
    #12

  13. I'm pretty sure the ordinal position in this context starts at 1, not 0. I'd
    have to try it to be sure.
    The ordinal position refers to the columns that appear in the select list,
    not to the columns as they appear in the table. Of course, selstar makes the
    select list equal to the Access setup order.
     
    Bob Barrows [MVP], Sep 11, 2006
    #13
  14. Jimmy

    Evertjan. Guest

    Bob Barrows [MVP] wrote on 11 sep 2006 in
    microsoft.public.inetserver.asp.general:
    You are right:

    Microsoft JET Database Engine error '80040e14'

    The Microsoft Jet database engine does not recognize '0' as a valid field
    name or expression.

    [Still a bit strange that field 0 in the star sense is field 1.]
     
    Evertjan., Sep 11, 2006
    #14
  15. It's znzlogous to the Ubound and LBound functions: the dimension
    identifiers start at 1, not 0.
     
    Bob Barrows [MVP], Sep 11, 2006
    #15
  16. Errmmm, that should, of course, be "analogous"
     
    Bob Barrows [MVP], Sep 11, 2006
    #16
  17. Hello, Hello... is this mic on??

    Have you read any of the responses to your question??
     
    Anthony Jones, Sep 11, 2006
    #17
  18. Jimmy

    Jimmy Guest

    yes and none have given a clear answer.
    its funny but the code i originally found on the aspfaq site is apparently
    what everyone uses to answer a question regarding random records in access,
    however it doesnt work!! LOL... pretty funny actually. but yes, i have
    confirmed that it does not work as written, and all of the "guru's" that
    were so quick to have an attitude in the beginning have since shut up
    because they cant look at the SQL query and figure out whats wrong with it.
    oh well, ill continue to use the function that i wrote which works fine. and
    if anyone else would like to point out how inefficient my function is, and
    offer another solution, have the sense to test it first!
     
    Jimmy, Sep 11, 2006
    #18
  19. Jimmy

    Larry Bud Guest

    That SQL definitely does NOT work in Access 2003. It ends up giving
    the column R the same value for each row.

    Here's the real answer

    SELECT TOP 1 email_address, Rnd(ID) FROM mytable ORDER BY 2;

    where mytable is your table that contains email_address and ID. ID is
    important, as it's a unique integer for each row. It doesn't matter
    how the rows are numbered, but as long as each one is unique, you get a
    different value for the 2nd column on each row. ORDER BY 2 orders by
    the 2nd column listed.

    NOW, PLEASE DO NOT TOP POST. Top posting is posting your answer to a
    message BEFORE or ABOVE or ON TOP of the previous messages. The
    problem is that if someone needs to read the whole posted thread, they
    have to start at the bottom and work their way to the top. It'd be
    like reading a newspaper column a paragraph at a time, starting with
    the last paragraph.

    Hope this helps.
     
    Larry Bud, Sep 11, 2006
    #19
  20. We have shut up because you spend more time whining that "it doesn't work"
    than giving useful details that would help us help you.

    I have to say I lost interest in helping you when you admitted on your
    *12th* message that you still didn't have a DB up and running with which to
    test all of the advice you were getting.

    Meet us halfway, and we can be an accommodating bunch. Make us work to give
    you advice, and you will get what you paid for: nothing.
     
    Dave Anderson, Sep 11, 2006
    #20
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