range with variable leading zeros

[yhvh]

I want to generate a range with variable leading zeros


x = [0010, 0210]
padding = len(x[1])

for j in range(x[0], x[1]):
print (url).join('%0(pad)d(jj)'+'.jpg') %{'pad'adding, 'jj':j}


This is syntactically incorrect, you can't insert a variable into the
string format options. Any ideas?

 

[Dan Bishop]

I want to generate a range with variable leading zeros

x = [0010, 0210]

You do realize that this is octal, right?

padding = len(x[1])

len is undefined for integers. Perhaps you meant "len(str(x[1]))".

for j in range(x[0], x[1]):
    print (url).join('%0(pad)d(jj)'+'.jpg') %{'pad'adding, 'jj':j}

This is syntactically incorrect, you can't insert a variable into the
string format options. Any ideas?

You can, however, do this:
'00123'

 

[alex23]

I want to generate a range with variable leading zeros

x = [0010, 0210]
padding = len(x[1])

for j in range(x[0], x[1]):
print (url).join('%0(pad)d(jj)'+'.jpg') %{'pad'adding, 'jj':j}

This is syntactically incorrect, you can't insert a variable into the
string format options. Any ideas?

Concatenate the parts of the pattern string first:

pat = '%0' + str(padding) + 'd'

 

[yhvh]

x = [0010, 0210]

You do realize that this is octal, right?

It's unfortunate I choose that, the numbers go beyond octal

len is undefined for integers.  Perhaps you meant "len(str(x[1]))".

Yes sorry it was late at night

You can, however, do this:
'00123'

This is exactly what I needed Thank-you kindly