Can someone explain to me how this works:\n\ndef printBackward(list):\n if list == None: return\n head = list\n tail = list.next\n printBackward(tail)\n print head,\n\n3 2 1\n\n\nThe printable value of node1 is 1, node2 is 2 and node 3 is 3.\n\nnode1.next is node2, node2.next is node3 and node3.next is None.\n\nThis might be painfully obvious, but I don't understand when the print \nstatement is getting called. If you call printBackward with node1, then \nyou skip the if statement, head becomes node1, tail becomes node2 and \nthen you call printBackward again with node2. During this call you call \nprintBackward again with node 3 and then the next time the if statement \nreturns. So when does the print happen, and how does it print 3 \ndifferent values? It seems like you wouldn't get to it until the last \ntime printBackward returns, and 'head' at that point would be 3, which \nis the first number printed. But doesn't it stop at this point? Where do \n2 and 1 come from?\n\nThanks!