Reg Ex Question

[sks]

I'm having trouble working out how to use a reg ex to replace certain
characters inside a string which contains some html.

String string = "<table>zmzmz<tr><td>Hello</td></tr></table>";

I want to replace the z's inside the <table> and <tr> tags with y's to get

<table>ymymy<tr>.... etc.

I can create my pattern,

Pattern pattern = Pattern.compile("<table>[(.*?z.*?)]{0,}<tr>");

get my matcher, but there doesn't seem to be a replace(int group, String
replacement) method or similar. Anyone help ?

 

[klynn47]

If you only want to replace the z with y, then use, replaceAll("z","y")

 

[Ann]

I'm having trouble working out how to use a reg ex to replace certain
characters inside a string which contains some html.

String string = "<table>zmzmz<tr><td>Hello</td></tr></table>";

I want to replace the z's inside the <table> and <tr> tags with y's to get

<table>ymymy<tr>.... etc.

This is not valid html is it?

 

[anonymous]

I'm having trouble working out how to use a reg ex to replace certain
characters inside a string which contains some html.

String string = "<table>zmzmz<tr><td>Hello</td></tr></table>";

I want to replace the z's inside the <table> and <tr> tags with y's to get

<table>ymymy<tr>.... etc.

I can create my pattern,

Pattern pattern = Pattern.compile("<table>[(.*?z.*?)]{0,}<tr>");

get my matcher, but there doesn't seem to be a replace(int group, String
replacement) method or similar. Anyone help ?

Well, String.replaceAll(String, String) takes a regex as its first
argument, so if you can create the pattern, it should be simple.

 

[Aquila Deus]

This is not valid html is it?

Valid html? you mean something like "<validhtml:table
xmlns:validhtml='http://www.w3.org/1999/xhtml'><validhtml:tr><validhtml:td>That's
valid html!</validhtml:td></validhtml:tr></validhtml:table>"

 

[Alan Moore]

This is a two-level operation: locate the range of text you want to
work in with one regex, then use a different regex to do a replacement.
The regex API doesn't provide such a facility, but you can roll your
own. Here's one way:

//==== code ========================================================

import java.util.regex.*;

class Test
{
public static void main(String[] args)
{
String input = "<table>zmzmz<tr><td>Hello</td></tr></table>";

Pattern p = Pattern.compile("(?<=<table>)[^<]+(?=<tr>)");
Matcher m = p.matcher(input);
StringBuffer sb = new StringBuffer();
while (m.find())
{
m.appendReplacement(sb, "");
sb.append(m.group().replaceAll("z", "y"));
}
m.appendTail(sb);

System.out.println(sb.toString());
}
}

//==================================================================