Regexp and multiple groups (with repeats)

[mk]

Hello,

>>> r=re.compile(r'(?:[a-zA-Z]([\\/]\w+)+')
>>> r.search(r'c:/tmp/spam/eggs').groups()

('/eggs',)

Obviously, I would like to capture all groups:
('/tmp', '/spam', '/eggs')

But it seems that re captures only the last group. Is there any way to
capture all groups with repeat following it, i.e. (...)+ or (...)* ?

Even better would be:

('tmp', 'spam', 'eggs')

Yes, I know about re.split:

>>> re.split( r'(?:\w?[/\\]', r'c:/tmp/spam\\eggs/' )

['', 'tmp', 'spam', '', 'eggs', '']

My interest is more general in this case: how to capture many groups
with a repeat?

Regards,
mk

 

[Neil Cerutti]

Hello,

r=re.compile(r'(?:[a-zA-Z]([\\/]\w+)+')
r.search(r'c:/tmp/spam/eggs').groups()

('/eggs',)

Obviously, I would like to capture all groups:
('/tmp', '/spam', '/eggs')

You'll have to do something else, for example:

s = re.compile(r'(?:[a-zA-Z]')
n = re.compile(r'[\\/]\w+')
m = s.match('c:/tmp/spam/eggs')
n.findall(m.string[m.end():])

['/tmp', '/spam', '/eggs']