replacing this backlash (\) with no backlash

[Devop]

hi.

I have been replacing string with backslas (\) with an other without
backlash.

This is part of the code
The reason i use \ in front of $ is that , $ is included in my search.

But when i replaced with the second variable, i get \${string2} - i
love you & (see the backlash is with me again ? how can i ignore this
backlash? . I want to get just {string2} - i love you &

my $first = '\${string1} &';
my $second = '\${string2} - i love you &';


$change =~ s/$first/$second/ms;


rgds

 

[Beable van Polasm]

I have been replacing string with backslas (\) with an other without
backlash.

This is part of the code
The reason i use \ in front of $ is that , $ is included in my search.

But when i replaced with the second variable, i get \${string2} - i
love you & (see the backlash is with me again ? how can i ignore this
backlash? . I want to get just {string2} - i love you &

my $first = '\${string1} &';
my $second = '\${string2} - i love you &';

I'm not sure I understand the problem. Would this work?

my $second = '{string2} - i love you &';

$change =~ s/$first/$second/ms;

--

 

[Devop]

The problem is i need the $ sign in the search and i have to use \ so that $
will not have a value

But how can i ignore \ in the substitution operation ?

rgds

 

[Anno Siegel]

-=-=-=-=-=-

hi.

I have been replacing string with backslas (\) with an other without
backlash.

This is part of the code
The reason i use \ in front of $ is that , $ is included in my search.

But when i replaced with the second variable, i get \${string2} - i
love you & (see the backlash is with me again ? how can i ignore this
backlash? . I want to get just {string2} - i love you &

my $first = '\${string1} &';

^
That backslash has no function in single quotes, it is included literally
in your string. Print out "$first" before the substitution to see it.

my $second = '\${string2} - i love you &';

Since your substitution does nothing about a literal backslash, it stays in.
You don't want to "ignore" the backslash, you don't want to put it in the
original string in the first place.

my $first ='${string1} &';

Anno