simple for loop i find not coherent

[papoupapa]

Hi

I reay think // A should be (nbr_entry != 0) || (i < NMAX) instead
of (nbr_entry != 0) && (i < NMAX)
As it's working, to my understanding, the second body of the for loop
is being read from the left to the right.

int main()
{
const int NMAX = 5 ;
vector<int>Numbers(NMAX) ;
int nbr_entry = 1 ;
int i, j ;

cout << "\nThis program reads a sequence of numbers \n" ;

j = 0 ;
nbr_entry = 1 ;
for (i = 0 ; (nbr_entry != 0) && (i < NMAX) ; i++, j++) // A
{
cout << "\nValue " << i+1 << " : " ;
cin >> nbr_entry ;
Numbers = nbr_entry ;
}

cout << "\n\nNumbers entered : \n" ;

for (i = 0 ; i < j ; i++)
cout << "Value " << i+1 << ": " << Numbers << "\n" ;


cout << "\n\n" ;
system("pause") ;
return 0 ;
}

 

[Ian Collins]

Hi

You asked almost the same question on c.l.c, very confusing!

I reay think // A should be (nbr_entry != 0) || (i< NMAX) instead
of (nbr_entry != 0)&& (i< NMAX)

Why? You want to keep reading while both conditions are true, not just one.

As it's working, to my understanding, the second body of the for loop
is being read from the left to the right.

int main()
{
const int NMAX = 5 ;
vector<int>Numbers(NMAX) ;
int nbr_entry = 1 ;
int i, j ;

cout<< "\nThis program reads a sequence of numbers \n" ;

j = 0 ;
nbr_entry = 1 ;
for (i = 0 ; (nbr_entry != 0)&& (i< NMAX) ; i++, j++) // A
{
cout<< "\nValue "<< i+1<< " : " ;
cin>> nbr_entry ;
Numbers = nbr_entry ;
}

cout<< "\n\nNumbers entered : \n" ;

for (i = 0 ; i< j ; i++)
cout<< "Value "<< i+1<< ": "<< Numbers<< "\n" ;


cout<< "\n\n" ;
system("pause") ;
return 0 ;
}